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pantera1 [17]
3 years ago
12

1 mole of CH4 contains ________molecules

Chemistry
1 answer:
laila [671]3 years ago
7 0

1 mole contains 6.023 *10^23 molecules

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Very small pka. can also be - pka. 
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The result of the procedure is that the copper strip should go through oxidation.

<h3>How to explain the procedure?</h3>

The copper strip should be considered as the anode and the nail should be considered as the cathode.

The anode is the electrode of an electrochemical cell at which oxidation occurs. The anode should be + while the cathode should be negative. Both should be placed in the tank that should be filled with the electrolyte solution.

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How did Altair begin
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Water enters the atmosphere as water vapor when liquid water on Earth's surface____. Can you please fill in the blank?
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A voltaic cell is constructed with two silver-silver chloride electrodes, where the halfreaction is AgCl (s) + e- → Ag (s) + Cl-
densk [106]

<u>Answer:</u> The cell potential of the cell is +0.118 V

<u>Explanation:</u>

The half reactions for the cell is:

<u>Oxidation half reaction (anode):</u>  Ag(s)+Cl^-(aq.)\rightarrow AgCl(s)+e^-

<u>Reduction half reaction (cathode):</u>  AgCl(s)+e^-\rightarrow Ag(s)+Cl^-(aq.)

In this case, the cathode and anode both are same. So, E^o_{cell} will be equal to zero.

To calculate cell potential of the cell, we use the equation given by Nernst, which is:

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Cl^{-}]_{diluted}}{[Cl^{-}]_{concentrated}}

where,

n = number of electrons in oxidation-reduction reaction = 1

E_{cell} = ?

[Cl^{-}]_{diluted} = 0.0222 M

[Cl^{-}]_{concentrated} = 2.22 M

Putting values in above equation, we get:

E_{cell}=0-\frac{0.0592}{1}\log \frac{0.0222M}{2.22M}

E_{cell}=0.118V

Hence, the cell potential of the cell is +0.118 V

6 0
3 years ago
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