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Maurinko [17]
4 years ago
5

How large must the coeffficient of static friction be between the tires and the road if a car is to round a level curve of radiu

s 120 m at a speed of 120 km/h Express your answer using two significant figures.
Physics
1 answer:
m_a_m_a [10]4 years ago
5 0

Answer:

Coefficient of static friction required = 0.94

Explanation:

Coefficient of static friction required =\frac{v^2}{gR}

Velocity, v = 120 km/h = 33.33 m/s

g = 9.81 m/s²

R = 120 m

Coefficient of static friction required=\frac{33.33^2}{9.81\times 120}=0.94

Coefficient of static friction required = 0.94

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(b)

Immediately prior to the explosion, the ball is at the maximum height.  Here, the vertical velocity is 0 m/s, and the horizontal velocity is constant at 25 m/s.

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Momentum is conserved before and after the explosion.

In the x direction:

m vx = ma vax + mb vbx

m (25) = (⅓ m) (0) + (⅔ m) (vbx)

25m = (⅔ m) (vbx)

25 = ⅔ vbx

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And in the y direction:

m vy = ma vay + mb vby

m (0) = (⅓ m) (0) + (⅔ m) (vby)

0 = (⅔ m) (vby)

vby = 0 m/s

Since the vertical velocity hasn't changed, and since Fragment B lands at the same height it was launched from, it will have a vertical velocity equal in magnitude and opposite in direction as its initial velocity.

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And the horizontal velocity will stay constant.

vx = 37.5 m/s

The velocity vector is (37.5 i - 13 j) m/s.  The magnitude is:

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