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VLD [36.1K]
3 years ago
5

A pool ball is rolling at a velocity of 12 cm/s to the right when it is hit by another ball. It continues moving right at a velo

city of 21 cm/s. If the collision lasts 0.45 seconds, what is the ball's acceleration?
A.+9 cm/s2
B.20 cm/s2 to the right
C.26 cm/s2 to the right
D.+46 cm/s2
Physics
1 answer:
madam [21]3 years ago
6 0

Answer:

B

Explanation:

Acceleration = rate of change in velocity

a = (21-12)/(0.45) = 20cm/s^2

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Big Ben, a large artifact in England, has a mass of 1x10^8 kilograms and the Empire State Building 1x10^9 kilograms. The distanc
TiliK225 [7]

Answer:

The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N

Explanation:

The question relates to the force of gravity experienced between two bodies

The given parameters are;

The mass of Big Ben, M₁ = 1 × 10⁸ kg

The mass of the Empire State Building, M₂ = 1 × 10⁹ kg

The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters

By Newton's Law of gravitation, we have;

F=G \times \dfrac{M_{1} \times M_{2}}{r^{2}}

Where;

F = The force exerted by Big Ben on the Empire State Building and vice versa

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

M₁, M₂, and r are the given parameters

By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;

F=6.67430 \times 10^{-11} \times \dfrac{1 \times 10^8 \times 1 \times 10^9}{(5,000,000)^{2}} = 2.66972 \times 10^{-7}

The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.

3 0
3 years ago
A 45.2 kg softball player slides across dirt with Uk=0.340. What is her acceleration?
alisha [4.7K]

Answer:

the ball didnt hit my face so

Explanation:

8 0
3 years ago
A rightward force of 12.0 N is applied to a 2.0-kg object to accelerate it across a horizontal
ad-work [718]

Answer:

below

Explanation:

Net accelerating force becomes  12-8 = 4 N

F = ma

4 = 2 * a

a = 2 m/s^2

8 0
1 year ago
In the demolition of an old building, a 1,300 kg wrecking ball hits the building at 1.07 m/s2. Calculate the amount of force at
Y_Kistochka [10]

Answer: F = 1391 N

Explanation:

The information given to you are:

Mass M = 1300 kg

Acceleration a = 1.07 m/s^2

The magnitude of the force striking the building will be

F = ma

Where

F = force

Substitute mass M and acceleration a into the formula

F = 1300 × 1.07

F = 1391 N

Therefore, the wrecking ball strikes the building with a force of 1391 N

3 0
3 years ago
A 2.5 kg table can hold kg of weight. what is its structural efficiency?
Lorico [155]
It's (whatever number comes after 'hold') divided by 2.5 .
6 0
3 years ago
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