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3 years ago

WHY light travel in straight line?reason?

2 answers:

8 0

Light travels in a straight line because it doesn't usually interact with its medium. When it does it is called refraction.

EleoNora [17]3 years ago

8 0

The reason light travels in a straight line is because it doesn't interact with its own medium.

I hope this helped! Good luck, fam!

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An atom with two protons, three neutrons and two electrons would have a mass of about how many atomic mass units?

Katarina [22]

The answer is 5 amu.

8 0

3 years ago

A body from the top of a 180 m high mountain is abandoned. Disregarding air resistance and adopting g = 10m / s2, determine:

elena55 [62]

Answer:

1) 6 seconds

2) 60 m/s

Explanation:

Given:

Δy = 180 m

v₀ = 0 m/s

a = 10 m/s²

1) Find t.

Δy = v₀ t + ½ at²

180 m = (0 m/s) t + ½ (10 m/s²) t²

t = 6 s

2) Find v.

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (10 m/s²) (180 m)

v = 60 m/s

4 0

3 years ago

Short-wavelength radiation from the Sun passes through a planet's atmosphere but some of the outgoing long-wavelength energy is

serious [3.7K]

Answer:Greenhouse effect

Explanation:

Short wavelength radiation from the sun passes through a planet's atmosphere but some of the outgoing long-wavelength energy is absorbed and radiated again this process is known as Green house effect which increases the temperature of earth and as a result causes more to be trapped inside earth atmosphere.

8 0

3 years ago

Deduce a value for the latent heat of evaporation Lv of water. State clearly any simplifying assumptions that you make. Estimate

Stolb23 [73]

Find the below attachment

5 0

3 years ago

Read 2 more answers

The star Rho1 Cancri is 57 light-years from the earth and has a mass 0.85 times that of our sun. A planet has been detected in a

s344n2d4d5 [400]

Answer:

82780.42123 m/s

14.45 days

Explanation:

m = Mass of the planet

M = Mass of the star = $0.85\times 1.989\times 10^{30}\ kg=1.69065\times 10^{30}\ kg$

r = Radius of orbit of planet = $0.11\times 149.6\times 10^{9}\ m=16.456\times 10^{9}\ m$

v = Orbital speed

The kinetic and potential energy balance is given by

$\frac{GMm}{r^2}=\frac{mv^2}{r}\\\Rightarrow v=\sqrt{\dfrac{Gm}{r}}\\\Rightarrow v=\sqrt{\dfrac{6.67\times 10^{-11}\times 1.69065\times 10^{30}}{16.456\times 10^{9}}}\\\Rightarrow v=82780.42123\ m/s$

The orbital speed of the star is 82780.42123 m/s

The orbital period is given by

$t=\frac{2\pi r}{v}\\\Rightarrow t=\dfrac{2\pi \times 16.456\times 10^{9}}{82780.42123}\\\Rightarrow t=1249040.48419\ seconds=\dfrac{1249040.48419}{24\times 60\times 60}=14.45\ days$

The orbital period is 14.45 days

5 0

2 years ago