<h3>
Answer:</h3>
Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.
<h3>
Explanation:</h3>
From the questions we are given;
4FeS₂(s) + 11O₂(g) → 2Fe₂O₃(s) + 8SO₂(s)
- Moles of FeS₂ are 26.62 moles
- Moles of Oxygen, O₂ are 59.44 moles
We are supposed to determine the limiting and excess reactants;
- From the equation of the reaction given; 4 moles of FeS₂ required 11 moles of Oxygen gas.
Working with the amount of reactants given;
- 26.62 moles of FeS₂ will require 73.205 moles of O₂ and only 59.44 moles of O₂ are available.
- On the other hand 59.44 moles of O₂ requires 21.615 moles of FeS₂, and we are given 26.62 moles of FeS₂ which means FeS₂ is in excess.
Conclusion;
We can conclude that Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.
Formula M1V1 =M2V2
1.5 * 100 = M2 *300
M2 = 1.5*100/300= 0.5.
Answer: the molarity is 0.5M.
Answer:
(a) Molar mass of ca= 40g/mol
(b) O2= 16 * 2 = 32g/mol
Use the group numbers to determine the number of valence electrons. The Group number of a non-transition metal can be used to find the number of valence electrons in an atom of that element. The ones place of the group number is the number of valence electrons in an atom of these elements.