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vitfil [10]
3 years ago
5

Gravitational potential energy (U) depends on three things: the object’s mass (m), its height (h), and gravitational acceleratio

n (g), which is 9.81 m/s2 on Earth’s surface: U = mgh Energy is measured in joules (J). One joule is equal to one 1 kg•m2/s2. When calculating the energy of an object, it is helpful to convert the mass and height to kilograms and meters.
A. What is the mass of the 50-gram car, in kilograms?

B. Set Hill 1 to 75 cm and the other hills to 0 cm. What is the height in meters?

C. What is the potential energy of the car, in joules?
Physics
2 answers:
Viefleur [7K]3 years ago
8 0

A. 500N

B. 0.75 m

C. 7865432J


adoni [48]3 years ago
7 0

Explanation:

A. Mass of the car ,m = 50 g

1 g = 0.001 kg

50 g = 0.001 × 50 kg = 0.05 kg

B. Height of hill ,h= 75 cm = 0.75 m

1 cm = 0.01 m

Height of other hill ,h' = 0 cm = 0 m

C. Gravitational potential energy (U):

U=mgh

Mass of car = m = 0.05 kg

Height at which car is = h = 0.75 m

U= 0.05 kg\times 0.75 m\times 9.8 m/s^2=0.3675 kg/m^2/s^2=0.3675 J

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First find the time it takes for the ball to reach the ground using the vertical component of its position vector:

y=y_0+v_{0y}t+\dfrac12a_yt^2

\implies0=100\,\mathrm m+\dfrac12\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2

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Meanwhile, the horizontal component of the ball's position vector is

x=x_0+v_{0x}t+\dfrac12a_xt^2

\implies x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)t

After about 4.52 s, the ball has traveled a horizontal distance of

x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)(4.52\,\mathrm s)=180.8\,\mathrm m

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