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Lady_Fox [76]
3 years ago
12

Which of the following criteria do astronomers use to classify an object as a planet? orbits a star gravity makes spherical at l

east as large as mercury clears orbits of other objects
Physics
2 answers:
scoray [572]3 years ago
4 0
The correct answer is Orbits a star, gravity makes it spherical, and clears orbits of other objects. Planets can be smaller than mercury so it's not a criterium.
Flauer [41]3 years ago
3 0

The correct answer of the question is : A) Orbits a star, B) Gravity makes spherical and D) Clear orbits of other objects.

EXPLANATION :

The classification of a celestial object to be a planet depends on some parameters.

The most important thing about the planet is that it must clear its orbit. It means it won't share its orbit with other planets. Otherwise, it will be considered as a dwarf planet.

The second thing is that it must move around any stars. The star becomes the centre of that solar system around which planets start revolving in different orbits.

The third thing is that planets are approximately spherical in shape.

The size of the planets does not play a crucial role in the classification of planets. Planets may be smaller than mercury also.

Hence, all the options except the third one are suitable.



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Hi, I am having some difficulties in solving this question. Could someone please explain this question to me in detail. The thin
aniked [119]

Answer:

a) 3.0×10⁸ m

b) 0 m

Explanation:

Displacement is the distance from the starting position to the final position.

a) In half a year, the Earth travels from one point on the circle to the point on the exact opposite side of the circle (from 0° to 180°).  The distance between the points is the diameter of the circle.

x = 2r

x = 2 (1.5×10⁸ m)

x = 3.0×10⁸ m

b) In a full year, the Earth travels one full revolution, so it ends up back where it started.  The displacement is therefore 0 m.

8 0
3 years ago
Assume you drink 250ml of soda out of a 1 liter soda bottle. how many liters are left?
charle [14.2K]

The correct answer is 0.75 liters.

<h3>Briefing:</h3>

One liter of soda produced 250 ml of beverage.

1 liter is equal to 1000 milliliters.

250 ml was consumed, or 250/1000 or 0.25 liter.

There was 1 - 0.25 liters of soda left

0.75 liter of soda was left and the correct answer is 0.75 liter.

<h3>What is a liter of water?</h3>

Four glasses of water make up one liter, to be precise.

Let us understand this using the following explanation. Despite the fact that there is no set standard size for glasses, their capacity varies. In contrast, we calculate that a liter holds 32 ounces and a glass holds 8 ounces of water.

<h3>How are liters measured?</h3>

Convert the object's dimensions into centimeters before performing the volume calculation in litres. Next, determine a shape's volume using the volume formula. For instance, you could use Volume = length times width times height to determine the volume of a cube, and the result would be in cubic centimetres.

To know more about Liters visit:

brainly.com/question/25546396

#SPJ4

5 0
2 years ago
A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 5.12 g coins stacked over the 24.2 cm mark, th
pashok25 [27]

Answer:

The mass of the meter stick is  1.66054054054g

Explanation:

Here since the meter stick is in equilibrium position its net torque and net force should be equal to zero

      Since at the begging the meter stick is balanced at center of the meter stick that means its center of mass should be present at 50.0cm

Now lets consider the later case where stick is balanced by two 5.12 g coins .

Here torque due to two coins = t_{c} = 5.12\times(27.8-24.2)\times2\times9.8

  Torque due to weight of meter stick =  t_{m} =  m\times(50-27.8)\times9.8

  where m = mass of the meter stick

    Here t_{c} = t_{m}.

Upon equating we will be getting mass of the meter stick =1.66054054054g

4 0
3 years ago
An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
sergiy2304 [10]

To solve this problem it is necessary to apply the concepts related to hydrostatic pressure or pressure due to a fluid.

Mathematically this pressure is given under the formula

P_h = \rho g h

Where,

\rho = Density

h = Height

g = Gravitational acceleration

Rearranging in terms of g

g = \frac{P_h}{\rho h}

our values are given as

P_h = 1.1 atm (\frac{101325Pa}{1atm}) = 111457.5Pa

\rho = 1000kg/m^3

h = 12.3m

Replacing we have

g = \frac{111457.5}{(1000)(12.3)}

g = 9.061m/s^2

Therefore the gravitational acceleration on the planet's surface is 9.061m/s^2 (Almost the gravity of the Earth)

3 0
3 years ago
How is photon energy calculated? (choose 2)
raketka [301]
Using Placks’s constant and frequency
5 0
3 years ago
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