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3 years ago

Find the sum of the vectors:10km west.5 km south

Physics

1 answer:

patriot [66]3 years ago

8 0

Answer:

11.2km

Explanation:

Using Pythagoras theorem

R² = 10² + 5²

R² = 100 + 25

R² = 125

R = √125

R = 11.2km

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A cylinder of compressed gas has a pressure of 488.2 kPa. The next day the cylinder of gas has a

Luda [366]

Answer:

20 °C

Explanation:

Ideal gas law:

PV = nRT

Rearranging:

P / T = nR / V

Since n, R, and V are constant:

P₁ / T₁ = P₂ / T₂

488.2 kPa / T = 468 kPa / 281.15 K

T = 293.29 K

T = 20.1 °C

Rounded, the temperature was 20 °C.

6 0

3 years ago

Suppose a woman raises a 65 N object in 2m in 4 seconds.

Novosadov [1.4K]

Answer:

$\huge\boxed{\sf P.E = 130\ Joules}$

$\huge\boxed{\sf P = 32.5\ Watts}$

Explanation:

<u>Given Data:</u>

Weight = W = 65 N

Height = h = 2 m

Time = t = 4 secs

<u>Required:</u>

Power = P = ?

Work Done in the form of Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = Wh

P = P.E. / t

<u>Solution:</u>

P.E. = (65)(2)

P.E = 130 Joules

P = P.E. / t

P = 130 / 4

P = 32.5 Watts

$\rule[225]{225}{2}$

Hope this helped!

8 0

3 years ago

A 8.4-mH inductor carries a current I = Imaxsin ωt, with Imax = 4.00 A and f = ω/2π = 60.0 Hz. What is the self-induced emf as a

Aleks04 [339]

Answer:

E= -3.166 cosωt V

Explanation:

Given that

I = Imax sinωt

L= 8.4 m H

Imax= 4 A

f = ω/2π = 60.0 Hz

ω = 120π rad/s

We know that self induce E given as

$E=-L\dfrac{dI}{dt}$

$\dfrac{dI}{dt}= Imax \ \omega\ cos\omega t$

$E=-L\times Imax \ \omega\ cos\omega t$

$E=-8.4\times 120\times \pi \ cos\omega t$

E= -3166.72 cosωt m V

E= -3.166 cosωt V

This is the induce emf.

3 0

3 years ago

The order of elements in the periodic table is based on?

ahrayia [7]

It is based on atomic number, which is the number of protons in the nuclei of the atoms of an element.

3 0

4 years ago

Read 2 more answers

Is there any change in the pressure of container filled with water when the volumed is increased

marshall27 [118]

Not really the volume of a container is simply length X width X depth so just how big the container unless the water is pressurized by some sort of weight or if the containers air pressure is lowered

7 0

3 years ago