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Anna71 [15]
3 years ago
8

Ceres has an orbital semi-major axis = 2.768 AU. What is Ceres’ orbital period?

Physics
1 answer:
Doss [256]3 years ago
6 0

Answer: 4.6 years

Explanation:

According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period T of a planet is proportional to the cube of the semi-major axis a (size) of its orbit”: </em>

<em />

T^{2}\propto a^{3} (1)  

However, if T is measured in Earth years, and a is measured in astronomical units (unit equivalent to the distance between the Sun and the Earth), equation (1) becomes:  

T^{2}=a^{3} (2)  

Knowing a=2.768 AU and isolating T from (2):  

T=\sqrt{a^{3}} (3)  

T=\sqrt{(2.768 AU)^{3}} (4)  

Finally:  

T=4.6 years This is Ceres' orbital period

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