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nika2105 [10]
3 years ago
14

Use the figure to determine in what direction the north magnetic pole of the compass will point. What type of magnetic pole is t

he compass pointing toward?

Physics
1 answer:
Marat540 [252]3 years ago
8 0
The north magnetic pole of the compass will point north. The compass is pointing toward the south magnetic pole because opposite poles attract while like poles repel. This means that the north magnetic pole of the compass is actually attracted to the south magnetic pole of the Earth as if it was a magnet as well. 
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Answer:

Distance is 50m

Displacement is 0m

Explanation:

Distance is based on the amount of length you covered, regardless of where you end.

Displacement only considered where you started and where you ended, which is at the same spot in this case. Therefore, no displacement.

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2 years ago
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3 years ago
In the most common isotope of Hydrogen the nucleus is made out of a single proton. When this Hydrogen atom is neutral, a single
FinnZ [79.3K]

Answer:

The ratio of electric force to the gravitational force is 2.27\times 10^{39}

Explanation:

It is given that,

Distance between electron and proton, r=4.53\ A=4.53\times 10^{-10}\ m

Electric force is given by :

F_e=k\dfrac{q_1q_2}{r^2}

Gravitational force is given by :

F_g=G\dfrac{m_1m_2}{r^2}

Where

m_1 is mass of electron, m_1=9.1\times 10^{-31}\ kg

m_2 is mass of proton, m_2=1.67\times 10^{-27}\ kg

q_1 is charge on electron, q_1=-1.6\times 10^{-19}\ kg

q_2 is charge on proton, q_2=1.6\times 10^{-19}\ kg

\dfrac{F_e}{F_g}=\dfrac{kq_1q_2}{Gm_1m_2}

\dfrac{F_e}{F_g}=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{6.67\times 10^{-11}\times 9.1\times 10^{-31}\times 1.67\times 10^{-27}}

\dfrac{F_e}{F_g}=2.27\times 10^{39}

So, the ratio of electric force to the gravitational force is 2.27\times 10^{39}. Hence, this is the required solution.

3 0
3 years ago
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scoundrel [369]

Centripetal force is given by F= mv²/r.

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Putting values,

F= mv²/r = 0.5× 3²/0.5 = 9 N

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I am pretty sure it is A and D
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