Give the principle, construction and working of Bourdan tube pressure gauge.
2 answers:
Answer:
<h3 /><h3>Working Principle Of Bourdon Gauge </h3><h3 />If a tube having oval cross section is subjected to pressure its cross section tends to change from oval to circular.
<h3>Construction of a Bordon Gauge </h3>Bourdon tube gauges consist of a circular tube.
One end of the tube is fixed while the other end is free to undergo elastic deformation under the effect of pressure.
Fixed end is open and pressure which is to be measured is applied at the fixed end.
Free end is closed and undergoes deformation under the effect of pressure.
Due to applied pressure the circular tube tends to uncoil and become straight along the dotted line.
<u>Working of Bourdon Gauge </u>
As the pressure is applied at the fixed end free end undergoes deformation.
The free end is attached with sector which further meshes with the pinion on which pointer is mounted.
Deformation of the pointer is transferred to pointer via this mechanism.
As a result point undergoes deflection and shows the pressure reading on calibrated dial.
PLEASE MARK ME AS A BRAINLIST
You might be interested in
Answer:
The pressure difference across hatch of the submarine is 3217.68 kpa.
Explanation:
Gauge pressure is the pressure above the atmospheric pressure. If we consider gauge pressure for finding pressure differential then no need to consider atmospheric pressure as they will cancel out. According to hydrostatic law, pressure varies in the z direction only.
Given:
Height of the hatch is 320 m
Surface gravity of the sea water is 1.025.
Density of water 1000 kg/m³.
Calculation:
Step1
Density of sea water is calculated as follows:
Here, density of sea water is, surface gravity is S.G and density of water is
.
Substitute all the values in the above equation as follows:
kg/m³.
Step2
Difference in pressure is calculated as follows:
pa.
Or
kpa.
Thus, the pressure difference across hatch of the submarine is 3217.68 kpa.
Answer:
minimum flow rate provided by pump is 0.02513 m^3/s
Explanation:
Given data:
Exit velocity of nozzle = 20m/s
Exit diameter = 40 mm
We know that flow rate Q is given as
where A is Area
minimum flow rate provided by pump is 0.02513 m^3/s