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emmasim [6.3K]
4 years ago
11

A particle is in a general circular motion (tangential speed is not constant). Which one of the following statements is always c

orrect. Explain reasoning for each. 1. The velocity of the particle is constant. 2. The velocity of the particle is tangent to the circle. 3. The acceleration of the particle is constant. 4. The acceleration of the particle is toward the center of the circle.
Physics
1 answer:
timurjin [86]4 years ago
7 0

Answer:

2. The velocity of the particle is tangent to the circle

Explanation:

1. The velocity of the particle is constant.

Incorrect

Reason : Since the tangential speed is not constant, hence the velocity of the particle is not constant.

2. The velocity of the particle is tangent to the circle.

Correct

Reason : In circular motion, the direction of velocity is always given by the tangent to the circle.

3. The acceleration of the particle is constant.

Incorrect

Reason : The tangential speed of the particle is not constant which in turn keeps changing the centripetal acceleration of the particle. hence the acceleration of the particle is not constant.

4. The acceleration of the particle is toward the center of circle.

Incorrect.

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A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity and displ
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a. -39.2 m/s; -78.4 m

b. -31.2 m/s; -46.4 m

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Explanation:

<h2>Part (a)</h2>

We are given/can infer these variables:

  • t = 4.0 s
  • a = -9.8 m/s²
  • v_0 = 0 m/s

We want to find the displacement and the final velocity of the rock.

  • Δx = ?
  • v = ?

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 0 + (-9.8)(4.0)
  • v = -9.8 * 4.0
  • v = -39.2 m/s

The final velocity of the rock is -39.2 m/s.

Now we can use this equation to find the displacement of the rock:

  • Δx = v_0 t + 1/2at²

Plug in the known variables into this equation.

  • Δx = 0 * 4.0 + 1/2(-9.8)(4.0)²
  • Δx = 1/2(-9.8)(4.0)²
  • Δx = -4.9 * 16
  • Δx = -78.4 m

The displacement of the rock is -78.4 m.

<h2>Part (b)</h2>

We are given/can infer these variables:

  • v_0 = 8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = 8.0 + (-9.8)(4.0)
  • v = 8.0 + -39.2
  • v = -31.2 m/s

The final velocity of the rock is -31.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = 8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = 32 - 4.9(16)
  • Δx = -46.4 m

The displacement of the rock is -46.4 m.

<h2>Part (c)</h2>

We are given/can infer these variables:

  • v_0 = -8.0 m/s
  • a = -9.8 m/s²
  • t = 4.0 s

We can use this equation to find the final velocity:

  • v = v_0 + at

Plug in the known variables into this equation.

  • v = -8.0 + (-9.8)(4.0)
  • v = -8.0 - 39.2
  • v = -47.2 m/s

The final velocity of the rock is -47.2 m/s.

We can use this equation to find the displacement:

  • Δx = v_0 t + 1/2at²

Plug in known variables:

  • Δx = -8.0(4.0) + 1/2(-9.8)(4.0)²
  • Δx = -32 - 4.9(16)
  • Δx = -110.4 m

The displacement of the rock is -110.4 m.

8 0
3 years ago
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