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3 years ago

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two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both

projectile strict the ground at the distance and time interval of both when they are in arir?

1 answer:

Sauron [17]3 years ago

3 0

Answer:

Yes, if θ = 45°

Explanation:

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Air at 25°C and 5 atm is throttled by a valve to 1 atm. If the valve is adiabatic and the change in kinetic energy is negligible

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Answer:

$T_{2} = 25^{\circ}C$

Solution:

As per the question:

Temperature, $T_{1} = 25^{\circ}C$

Pressure, $P_{1} = 5 atm[\tex]Now,We know that the process of throttling occurs in adiabatic conditions where no heat is transferred in between the system and the surrounding, i.e., Q = 0Thus no work is done in this process, i.e., W = 0Enthalpy also remains same from one state to the other state, i.e., [tex]\Delta h = 0$

Therefore, from the eqn:

$Q - W = \Delta h + \Delta KE$

We can write:

$\Delta h = h_{1} - h_{2} = 0$

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Thus

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where

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A laser beam is incident on two slits with a separation of 0.215 mm, and a screen is placed 5.45 m from the slits. an interferen

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Use: dsin(θ) = mλ where d is slit separation, m is fringe order (1 here), and
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A bowling ball has an initial momentum of +30 kg m/s and hits a stationary bowling pin. After the collision, the bowling ball le

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Momentum should be conserved. The momentum of both objects must balance with their initial and final momentum.

Let m1 and v1 be the mass and velocity of the bowling ball

And m2 and v2 be the mass and velocity of the bowling pin

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Explanation: Ganymede, Callisto, Titan are the moons of outer planets or gaseous planets which are made up of ice and rock. Callisto is an ice-covered moon and has no inner or outer activity and is considered basically geologically dead. Ganymede has rocky core and shows signs of tectonic activity, including long cracks in the crust and regions of young surface terrain. Titan has active geology of liquid hydrocarbons on the surface, rain back onto the surface and evaporation into the atmosphere. It has similar size, composition and mass to Ganymede and Callisto.

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3 years ago

Starting from rest, a solid sphere rolls without slipping down an incline plane. At the bottom of the incline, what does the ang

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Answer:

2/R*sqrt (g*s*sin(θ)) = w

Explanation:

Assume:

- The cylinder with mass m

- The radius of cylinder R

- Distance traveled down the slope is s

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- The slope of the plane θ

- Frictionless surface.

Solution:

- Using energy principle at top and bottom of the slope. The exchange of gravitational potential energy at height h, and kinetic energy at the bottom of slope.

ΔPE = ΔKE

- The change in gravitational potential energy is given as m*g*h.

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- Where I is the moment of inertia of the cylinder I = 0.5*m*R^2

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m*g*s*sin(θ) = 0.25*m*R^2*w^2

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