Question

Problem 02.061 For the given circuit, assume vS = 10 V, R1 = 9 Ω, R2 = 4 Ω, R3 = 4 Ω, R4 = 5 Ω, and R5 = 4 Ω. Reference Book & Resources Section Break Problem 02.061 5.value: 10.00 points Required information Problem 02.061.b Determine the power delivered by the source vS. (Round the final answer to two decimal places.) The power delivered by the source vS is W.]

Answer 1

Answer:

Ws=8.75 Watts

Explanation:

As per fig. of prob 02.061, it is clear that R5 and R4 are in parallel, its equivalent Resistance will be:

$\frac{1}{Req45}=\frac{1}{R4}+\frac{1}{R5}$

$\frac{1}{Req45}=\frac{1}{5}+\frac{1}{4}$

$\frac{1}{Req45}=0.2+0.25=0.45\\ Req45=2.22$

Now, this equivalent Req45 is in series with R3, therefore:

$Req345=R3+Req45\\Req345=4+2.22\\Req345=6.22$

This Req345 is in parallel with R2, i.e

$Req2345=(R2^{-1}+Req345^{-1} )^{-1}\\ Req2345=(4^{-1}+6.22^{-1} )^{-1} \\Req2345=2.43$

Now this gets in series with R1:

$Req12345=R1+Req2345\\Req12345=9+2.43\\Req12345=11.43$

Now, the power delivered Ws is:

$Ws=Vs*I=\frac{Vs^{2}}{Req} \\Ws=\frac{10^{2} }{11.43} \\Ws=8.75 Watts$