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3 years ago

1) Classify each of the following as either a solid, liquid or gas at room temperature.

Physics

1 answer:

SVEN [57.7K]3 years ago

5 0

Answer:

air gas

diamond solid

copper solid

candle wax solid or melted would be liquid

Explanation:

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If the range of the projectile is 4.3 m, the time-of-flight is T = 0.829 s, and air resistance is negligible, determine the foll

ankoles [38]

Answer

given,

range of the projectile = 4.3 m

time of flight = T = 0.829 s

$v =\dfrac{d}{T}$

$v =\dfrac{4.3}{0.829}$

v = 5.19 m/s

vertical component of velocity of projectile

v_y = gt'

$v_y = 9.8 \times {\dfrac{T}{2}}$

$v_y = 9.8 \times {\dfrac{0.829}{2}}$

$v_y =4.06\ m/s$

a) Launch angle

$\theta = tan^{-1}(\dfrac{v_y}{v})$

$\theta = tan^{-1}(\dfrac{4.06}{5.19})$

θ = 38°

b) initial speed of projectile

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{5.19^2 + 4.06^2}$

v = 6.59 m/s

c) maximum height reached by the projectile

$y_{max}=v_{avg}t'$

$y_{max}=\dfrac{1}{2}v_y\dfrac{T}{2}$

$y_{max}=\dfrac{1}{2}\times(g\dfrac{T}{2})\times\dfrac{T}{2}$

$y_{max}=\dfrac{gT^2}{8}$

7 0

3 years ago

If a baseball's velocity is increased to four times its original velocity, by what factor does its kinetic energy increase

jeyben [28]

Answer:

16 times

Explanation:

Original

KE(i) = 1/2mv²

After increasing

KE(f) = 1/2m(4v)²

KE(f) = 8mv²

KE(f)/KE(i) = 8 x 2 = 16

8 0

3 years ago

A swimming pool contains x (less than 0.02) grams of chlorine per cubic meter. the pool measures 5 meters by 50 meters and is 2

zubka84 [21]

The solution for this problem would be:(10 - 500x) / (5 - x)
so start by doing:
x(5*50*2) - xV + 5V = 0.02(5*50*2)
500x - xV + 5V = 10
V(5 - x) = 10 - 500x
V = (10 - 500x) / (5 - x)
(V stands for the volume, but leaves us with the expression for x)

3 0

3 years ago

A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.

Katen [24]

Answer:

9.4 m/s

Explanation:

The work-energy theorem states that the work done on an object is equal to the change in kinetic energy of the object.

So we can write:

$W=K_f - K_i$

where in this problem:

W = -36.733 J is the work performed on the car (negative because its direction is opposite to the motion of the car)

$K_i = 66,120 J$ is the initial kinetic energy of the car

$K_f$ is the final kinetic energy

Solving for Kf,

$K_f = W+K_i = -36,733+66,120=29,387 J$

The kinetic energy of the car can be also written as

$K_f = \frac{1}{2}mv^2$

where:

m = 661 kg is the mass of the car

v is its final speed

Solving, we find

$v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.4 m/s$

8 0

3 years ago

Parallel circuits are most likely to be used in which of the following?

lara31 [8.8K]

They're most likely to be used in a house because if you turn on a switch in ur house the rest of them stay off they don't turn on

6 0

3 years ago

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