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Bess [88]
3 years ago
13

A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The

linear density of the rope is 567 g/m. What is the amplitude of the wave? A1 =
Physics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

A = 2.43*10^{-3} m

Explanation:

power through string can be determined as shown in figure

P  = 2\pi ^2 HVA^2F^2

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

V = f *\lambda\lambda = \frac{v}{f}

therefore P  = 2\pi ^2 HVA^2(\frac{v}{f})^2

57.3 = \frac{2\pi ^2 * 0.567 *13.87^{3}* A^2}{(5.54*10^{-2})^2}

A = 2.43*10^{-3} m

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Answer:

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