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Bess [88]
3 years ago
13

A wave is sent along the first rope transmitting a power of 57.3 W. It has a wavelength of 5.54 cm and velocity of 13.87 m/s The

linear density of the rope is 567 g/m. What is the amplitude of the wave? A1 =
Physics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

A = 2.43*10^{-3} m

Explanation:

power through string can be determined as shown in figure

P  = 2\pi ^2 HVA^2F^2

Where

P = 57.3 W

V = 13.87 m/s

H = 567 g/m

we know that

V = f *\lambda\lambda = \frac{v}{f}

therefore P  = 2\pi ^2 HVA^2(\frac{v}{f})^2

57.3 = \frac{2\pi ^2 * 0.567 *13.87^{3}* A^2}{(5.54*10^{-2})^2}

A = 2.43*10^{-3} m

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Kazeer [188]

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Frequency, f, is how many cycles of an oscillation occur per second and is measured in cycles per second or hertz (Hz). The period of a wave, T, is the amount of time it takes a wave to vibrate one full cycle. These two terms are inversely proportional to each other: f = 1/T and T = 1/f.

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7 0
2 years ago
Frank has a paperclip. It has a mass of 12g and a volume of 3cm3. What is its density?​
Mkey [24]

Answer:

D = 4 g/cm³

Explanation:

Density = Mass / Volume

Step 1: Define

D = x

M = 12 g

V = 3 cm³

Step 2: Substitute

D = 12g/3 cm³

Step 3: Simplify

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4 0
2 years ago
Consider a golf ball with a mass of 45.9 grams traveling at 200 km/hr. If an experiment is designed to measure the position of t
Kipish [7]

Answer:

speed of golf ball is 1.15 × 10^{-30} m/s

and % of uncertainty in speed =  2.07 × 10^{-30} %

Explanation:

given data

mass = 45.9 gram = 0.0459 kg

speed = 200 km/hr = 55.5 m/s

uncertainty position Δx = 1 mm = 10^{-3} m

to find out

speed of the golf ball and  % of speed of the golf ball

solution

we will apply here heisenberg uncertainty principle that is

uncertainty position ×uncertainty momentum ≥ \frac{h}{4\pi }    ......1

Δx × ΔPx  ≥ \frac{h}{4\pi }

here uncertainty momentum ΔPx = mΔVx

and uncertainty velocity = ΔVx

and h = 6.626 × 10^{-34} Js

so put here all these value in equation 1

10^{-3} × 0.0459 × ΔVx =  \frac{6.626*10^{-34}}{4\pi }

ΔVx = 1.15 × 10^{-30} m/s

and

so % of uncertainty in speed = ΔV / m

% of uncertainty in speed =  1.15 × 10^{-30}  / 55.5

% of uncertainty in speed =  2.07 × 10^{-30} %

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Order these space notes in the bass clef from highest space to lowest space?
mamaluj [8]
Aware is 3(A) I hope this helps
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