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Sav [38]
4 years ago
7

What is a hypothesis?

Physics
2 answers:
sweet-ann [11.9K]4 years ago
6 0

Answer:

D!!!!!

Explanation:

A hypothesis is a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Vika [28.1K]4 years ago
6 0

Answer:

D. An educated guess about the outcome of an experiment.

Explanation:

Hypothesis is an educated guess about the outcome of an experiment.

Hope this helps ;) ❤❤❤

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Is this unbalanced force or is it balanced also is it technically acceleration?
Ivan

Answer:

Unbalanced

Explanation:

There is an acceleration. Look at the direction of the arrows.

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3 years ago
If the distance of a charged particle from a wire changes from 10cm to 20 cm , what happens to its magnetic field
postnew [5]

Answer:

i would say it decreases

Explanation:

bc as distance grows the fields decrease

IM NOT SURE tho

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Why do flames go upwards​
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3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.
Klio2033 [76]
  • Frequency=v=4.75×10^12Hz
  • Wavelength=?

We know

\boxed{\sf \lambda=\dfrac{C}{V}}

\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}

\\ \sf\longmapsto \lambda=0.631\times 10^{-4}m

\\ \sf\longmapsto \lambda=6.31\times 10^{-5}m

4 0
3 years ago
use the general formulas for gravitational force and centripetal force to derive the relationship between speed and orbital radi
MrRissso [65]

Answer:

v = \sqrt{\frac{GM}{r}}

Explanation:

The universal law of gravitation is defined as:

F = G\frac{Mm}{r^{2}}  (1)                

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

The centripetal force can be found by means of Newton's second law:

F = ma  (2)

Since it is a circular motion, the acceleration can be defined as:

a = \frac{v^{2}}{r}  (3)

Where v is the velocity and r is the orbital radius.

Replacing equation (3) in equation (2) it is gotten:

F = m\frac{v^{2}}{r}  (4)

Hence,

m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}

Then, v can be isolated:

mv^{2} = G\frac{Mmr}{r^{2}}

mv^{2} = G\frac{Mm}{r}

v^{2} = G\frac{Mm}{mr}

v^{2} = \frac{GM}{r}

v = \sqrt{\frac{GM}{r}}

So the relationship between speed and orbital radius is given by the expression v = \sqrt{\frac{GM}{r}}

8 0
3 years ago
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