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3 years ago

A. 2.0x1024 atoms of S to moles (3.3)

Chemistry

1 answer:

Fynjy0 [20]3 years ago

5 0

3.3 moles of sulfur

Explanation:

To find the number of moles knowing the number of atoms we use Avogadro's number to formulate the following reasoning:

if in 1 mole of sulfur (S) there are 6.022 × 10²³ atoms of sulfur (S)

then in X moles of sulfur (S) there are 2 × 10²⁴ atoms of sulfur (S)

X = (1 × 2 × 10²⁴) / (6.022 × 10²³)

X = 3.3 moles of sulfur

Learn more about:

Avogadro's number

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Calculate the number of moles equivalent to 12.7 gram of iodine molecule

Alexus [3.1K]

$\LARGE{ \boxed{ \purple{ \rm{Answer}}}}$

☃️ Chemical formulae ➝ $\sf{I_2}$

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}$

Solution:

❍ Molecular weight of $\sf{I_2}$

= 2 × 126.90

= 253.80

= 254 (approx.)

❍ Given weight: 12.7

Then, no. of moles,

⇛ No. of moles = 12.7 / 254

⇛ No. of moles = 0.05 moles

⚘ No. of moles of Iodine molecule in the given weight = 0.05 moles

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What is the formula of iron(iii) oxide?

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Answer:

Fe2O3

Explanation:

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Which of the following is a reason for cell division?

vekshin1

Answer:

D, to repair the damged cells is noy a reason that cells reproduce by siving in order to maintaon homeostasis.

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Which of the following is a physical

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Answer:

C. solid iodine subliming into a gas

Explanation:

A physical change is a change that is reversible and can be reversed back into the original product. The atoms and molecules undergoes some rearrangement in the physical change. The process of change in the state of matters are placed under physical change. Solid iodine sublimes into purple gas on heating. The gas is then changed back to iodine crystals after being cooled. Hence, this is an example of a physical change.

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How many grams of NaOH (MW = 40.0) are there in 500.0 mL of a 0.225 M NaOH solution?

Akimi4 [234]

Given: Molar mass of NaOH=40 g/mol

Volume of NaOH solution=500 mL

Molarity of solution=0.225 M

Molarity of solution is defined as number of moles of solute in 1 L of solution. Thus,

$M=\frac{n}{V}$

Thus, to calculate the mass of NaOH, first calculate its number of moles by rearranging the above equation and putting values of volume and number of moles.

$n=M\times V=0.225 M(\frac{ mol/L}{1 M})\times 500 mL(\frac{10^{-3} L}{1 mL})=0.1125 mol$

Now, number of moles are related to mass as follows:

$n=\frac{m}{M}$

Here, M is molar mass

Rearranging and putting the values of number of moles and molar mass thus,

$m=n\times M=0.1125 mol\times 40 g/mol=4.5 g$

Therefore, mass of NaOH in 500 mL of 0.225 M NaOH solution is 4.5 g.

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