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alexira [117]
3 years ago
9

Polyatomic ions such as ammonium ions and nitrate ions are ions that consist of

Chemistry
1 answer:
gregori [183]3 years ago
5 0
More than one atom

- Hope this helps :)
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If I started with 42.00 L of oxygen (O2) gas, how many grams is that?
belka [17]

Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

5 0
2 years ago
To titrate 45.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the mo
gtnhenbr [62]
V ( HCl ) = 45.00 mL in liters : 45.00 / 1000 => 0.045 L

M ( HCl ) = ?

V ( NaOH ) = 25.00 / 1000 => 0.025 L 

M ( NaOH) = 0.2000 M

number of moles NaOH :

n = M x V = 0.2000 x 0.025 => 0.005 moles of NaOH

Mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl ---------- 1 mole NaOH
? mole HCl ---------- 0.005 moles NaOH

moles HCl = 0.005 x 1 / 1

= 0.005 moles of HCl :

M ( HCl ) = n / V

M ( HCl ) = 0.005 / 0.045

= 0.1111 M

hope this helps!




4 0
3 years ago
Which form of energy is directly related to the measure of the average kinetic energy of the particles in a substance?
marshall27 [118]
<span>The form of energy related to measurement of kinetic energy is heat energy. Basically, thermal energy is related to the measurement of molecula kinetics of a substance. It is due to the thermoagitation of the partices of the substances, which keep on moving. </span>
4 0
2 years ago
Read 2 more answers
4.60 mL of 0.1852 M HNO3 is titrated to the phenolphthalein indicator endpoint with 27.35 mL of a KOH solution. What is the mola
Kamila [148]

Answer:

M_{base}=0.0311M

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:

n_{acid}=n_{base}

Which in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the base (KOH) to obtain:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{4.60mL*0.1852M}{27.35mL}\\\\M_{base}=0.0311M

Regards!

4 0
2 years ago
WILL GIVE BRAINLIEST ANSWER
OleMash [197]
The correct Answer based on my calculations is C
7 0
3 years ago
Read 2 more answers
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