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stepladder [879]
3 years ago
14

During a routine check of the fluoride content of Gotham City's water supply, the given results were obtained from replicate ana

lyses of a single sample: 0.511 mg/L , 0.485 mg/L , 0.509 mg/L , 0.491 mg/L , and 0.521 mg/L . Determine the mean and 90% confidence interval for the average fluoride concentration in this sample.

Chemistry
1 answer:
dexar [7]3 years ago
5 0

Answer:

Mean = 0.503

Confidence interval = 0.513, 0.493

Explanation:

Further explanations and calculations are found in the attachment below

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C3H8 and CH4 are 2 compounds made from the same elements. This is an example of which law? A) Law of Conservation of Mass b) Law
Sphinxa [80]

C3H8 and CH4 are two compounds made from the same two elements, C and H. The ratios of C and H for both are round numbers.

Law of multiple proportions states that when two elements combine with each other to form more than one compound, the weights of one element that combine with a fixed weight of the other are in a ratio of small whole numbers.

So the ans is C) Law of Multiple Proportions

6 0
3 years ago
The balanced equation for the reaction of ammonia and oxygen is the following. 4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g) The stand
ale4655 [162]

Answer:

ΔS° = 180.5 J/mol.K

Explanation:

Let's consider the following reaction.

4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)

The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.

ΔS° = ∑np × S°p - ∑nr × S°r

where,

ni are the moles of reactants and products

S°i are the standard molar entropies of reactants and products

ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))

ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol

ΔS° = 180.5 J/K

This is the change in the entropy per mole of reaction.

7 0
3 years ago
How many moles of glucose does 1.2 x 10^24 molecules represent
sammy [17]
<h3>Answer:</h3>

2.0 mol C₆H₁₂O₆

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})
  2. Divide:                                                                                                                      \displaystyle 1.99269 \ mol \ C_6H_{12}O_6

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆

3 0
3 years ago
The graph shows the number of beans eaten by a random zocco. How many light red kidney beans were eaten on Day 7? How many dark
Tems11 [23]

Answer:

day 7   50  and day 8  40

Explanation:

3 0
3 years ago
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Twenty students were surveyed to find out how many hours of TV they watch during a school week. The results are shown to the rig
natulia [17]

Answer: 4.5

Explanation:

Just did it

8 0
2 years ago
Read 2 more answers
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