The student who did the most work is student 2 with 2500 Joules.
<u>Given the following data:</u>
To determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
<u>For </u><u>student 1</u><u>:</u>
Work done = 600 Joules
<u>For </u><u>student 2</u><u>:</u>
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
Read more: Read more: brainly.com/question/13818347
1. its must be B and 2. must be C
Answer:
1.10m/s
2.0.1m
3.5Hz
Explanation:
v=velocity, f=frequency and T=wavelength
1.v=ft
v=2x5
=10m
2.v=ft
100=1000T
divide both sides by 1000
T=0.1m
3.v=fT
25=5f
divide both sides by 5
f=5Hz
D. mechanical energy is transformed into sound energy.
Answer:
<h2>option C </h2><h2>decreasing its thickness and increasing its temperature. </h2>
Explanation:
<h2>Resistance is directly proportional to length and temperature of the wire and inversely to area.</h2>
<h3>if you increase the temperature the resistance will increase.(resistance is directly proportional to temperature)</h3>
<h3>if you decrease its thickness (area) then the resistance will increase ( resistance is inversely proportional to area)</h3>
hope it helps:)
