Answer:
No
Explanation:
The supplied information about the object and train is incomplete. Acceleration is the rate at which the velocity of a body changes with time. Here the velocity and time is not given
The sun is bigger, but has less mass than the earth
Answer:
24.8m/s
Explanation:
Given data
m1= 10kg
u1=25m/s
m2=17kg
u2=16m/s
v1=10m/s
v2=??
Applying the conservation of linear momentum
m1u1+m2u2=m1v1+m2v2
substitute
10*25+17*16=10*10+17*v2
250+272=100+17v2
522=100+17v2
522-100=17v2
422=17v2
Divide both sides by 17
v2= 422/17
v2= 24.8 m/s
Hence the velocity of the red cart is 24.8m/s in the opposite direction of the blue cart
Hold on and let's discuss this realistically.
Because of gravity, there are two forces between the Earth and me. One draws me toward the Earth. The strength of that force is what I call my "weight". The other force draws the Earth toward me, and has the same strength.
The strength of these forces depends on the masses of the Earth and me. If the strength just tripled, that means that at least one of us just picked up a lot more mass. If the Earth suddenly became three times as massive, then the weight of everything and everybody on it would suddenly triple, and I'm pretty sure it would be the end of all of us before too long.
If it was only MY mass that suddenly tripled, that would mean that I had gone tearing through my house and the neighbour's house, eating everything in sight including the 2 couches, 3 dogs, and 6 TVs. Naturally, just as you would expect, my weight changed from 207 to 621, and my skin is stretched really tight.
ooohhh
Answer:
At time 10.28 s after A is fired bullet B passes A.
Passing of B occurs at 4108.31 height.
Explanation:
Let h be the height at which this occurs and t be the time after second bullet fires.
Distance traveled by first bullet can be calculated using equation of motion
Here s = h,u = 450m/s a = -g and t = t+3
Substituting
Distance traveled by second bullet
Here s = h,u = 600m/s a = -g and t = t
Substituting
Solving both equations
So at time 10.28 s after A is fired bullet B passes A.
Height at t = 7.28 s
Passing of B occurs at 4108.31 height.
