Ask question

Ask question

All categories

3 years ago

9

A phone cord is 4.89 m long. The cord has a mass of 0.212 kg. A transverse wave pulse is produced by plucking one end of the tau

t cord. That pulse makes four round trips (down and back) along the cord in 0.617 s. What is the tension (N) in the cord? Hint: Four round trips is a total distance of eight lengths of the cord. (Answer between 100-300 N)

1 answer:

slega [8]3 years ago

5 0

Answer:

Tension in Cord=174 N

Explanation:

Given Data

L (Phone Cord Length)=4.89 m

m (Cord Mass)=0.212 Kg

T (Time for four trips)=0.617 s

Tension=?

Solution

V=λ×f

$V=\frac{8*4.89}{0.617}\\ V=63.4m/s$

$Sigma=\frac{mass}{length}\\ Sigma=\frac{0.212}{4.89}\\ Sigma=0.0433 \frac{kg}{m}$

$Wave Speed=\sqrt{\frac{Tension}{Sigma} }\\ \\V=\sqrt{\frac{T}{Sigma} }\\ V^{2}=\frac{T}{Sigma}\\ T=V^{2}*Sigma\\ T=(63.4)^{2}*(0.0433)\\ T=174 N$

You might be interested in

30 points ᖗ☯ ͟ل͜☯ᖘ

Butoxors [25]

1. Magnetic properties of a substance depends on the structure of its valence electrons. It has something to do with orbitals so I suggest you study about molecular geometry of a compound/substance firstIt's the way a substance's atoms fit together, being pulled and pushed from all sides equally. exists in metallic bonds <span>if a substance is said to be magnetic, it is simply attracted by a magnet. if it is paramagnetic, it is repelled by a magnet.

2.</span>The magnetic field will be perpendicular to the electric field and vice versa<span> An electric field is the area which surrounds an electric charge within which it is capable of exerting a perceptible force on another electric charge. A magnetic field is the area of force surrounding a magnetic pole, or a current flowing through a conductor, in which there is a magnetic flux. A magnetic field can be produced when an electric current is passed through an electric circuit wound in a helix or solenoid. The relationship that exists between an electric field and a magnetic field is one of electromagnetic interaction as a consequence of associating elementary particles. The electrostatic force between charged particles is an example of this relationship.</span>

6 0

3 years ago

What happens when an object is moved against gravity, such as rolling a toy car up a ramp?

BlackZzzverrR [31]

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

3 0

2 years ago

what is the relationship between the number of turns of the wire and electrical output of the generator?

xxTIMURxx [149]

The number of turns of wire is directly proportional to voltage.

The higher the number of turns of wire the higher the voltage

Since .

Power (output) of a generator = voltage x current. Therefore the higher the voltage the higher the output of the generator.

So, the higher the number of turns of wire the higher the output of the generator.

4 0

3 years ago

State the name given to the energy that is needed to melt the ice cube: latent __________.

Vaselesa [24]

Answer:

Explanation: heat of fusion

5 0

3 years ago

A factory worker pushes a 32.0 kgkg crate a distance of 4.0 mm along a level floor at constant velocity by pushing horizontally

Luda [366]

Answer:

a) The force that the worker must apply has a magnitude of 75.317 newtons.

b) The external force does a work of 0.301 joules.

c) The friction force does a work of -0.301 joules.

d) Both normal force and gravity have done a work of 0 joules.

e) The total work done on the crate is 0 joules.

Explanation:

a) As the crate is moving at constant velocity, we know that magnitude of the force done on the crate must be equal to the friction force. Hence, we must use the following formula:

$F = \mu\cdot m\cdot g$ (1)

Where:

$F$ - External force, in newtons.

$\mu$ - Coefficient of kinetic friction, no unit.

$m$ - Mass, in kilograms.

$g$ - Gravity acceleration, in meters per square second.

If we know that $\mu = 0.24$ , $m= 32\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the external force is:

$F = (0.24)\cdot (32\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$F = 75.317\,N$

The force that the worker must apply has a magnitude of 75.317 newtons.

b) The direction of the force is parallel to the direction of motion. The work done by this force ( $W_{F}$ ), in joules, is determined by this formula:

$W_{F} = F\cdot \Delta s$ (2)

Where $\Delta s$ is the distance travelled by the crate, in meters.

If we know that $F = 75.317\,N$ and $\Delta s = 0.004\,m$ , then the work done by the force is:

$W_{F} = (75.317\,N)\cdot (0.004\,m)$

$W_{F} = 0.301\,J$

The external force does a work of 0.301 joules.

c) The direction of the friction force is antiparallel to the direction of motion. The work done by this force ( $W_{f}$ ), in joules, is determined by this formula:

$W_{f} = -W_{F}$ (3)

$W_{f} = -0.301\,J$

The friction force does a work of -0.301 joules.

d) The direction of the normal force is perpendicular to the direction of motion. Therefore, no work is done due to normal force.

$W_{N} = 0\,J$

Likewise, no work is done by gravity.

$W_{g} = 0\,J$

Both normal force and gravity have done a work of 0 joules.

e) The total work is the sum of the works done by the external force and the friction force:

$W = W_{F}+W_{f}$

$W = 0.301\,J - 0.301\,J$

$W = 0\,J$

The total work done on the crate is 0 joules.

5 0

2 years ago