Answer:
aquarium vs the value of both obstacles
Answer:
Explanation:
Given that,
Efficiency of Carnot engine is 47%
η =47%=0.47
The wasted heat is at temp 60°F
TL=60°F
Rate of heat wasted is 800Btu/min
Therefore, rate of heat loss QL is
QL' = 800×60 =48000
The power output is determined from rate of heat obtained from the source and rate of wasted heat.
Therefore,
W' = QH' - QL'
Note QH' = QL' / (1-η)
W' = QL' / (1-η) - QL'
W'=QL' η / (1-η)
W'= 48000×0.47/(1-0.47)
W'=42566.0377 BTU
1 btu per hour (btu/h) = 0.00039 horsepower (hp)
Then, 42566.0377×0.00039
W'=16.6hp
Which is approximately 17hp
b. Temperature at source
Using ratio of wanted heat to temp
Then,
TH / TL = QH' / QL'
TH = TL ( QH' / QL')
Since, QH' = QL' / (1-η)
Then, TH= TL( QL' /QL' (1-η))
TH=TL/(1-η)
TL=60°F, let convert to rankine
°R=°F+459.67
TL=60+459.67
TL=519.67R
TH=519.67/(1-0.47)
TH=980.51R
Which is approximately 1000R
Answer: (C) The ball will accelerate to about 20 m/s.
Explanation: The ball is in free fall and no other but gravitational force acts on it. This means the ball will be subject to the gravitational acceleration, which is about 9.8 m/s^2. So after one additional second the ball will increase its velocity to (10+9.8) m/s = 19.8 m/s or approx. 20 m/s.
Answer:
(a)
(b)
(c)
Explanation:
First change the units of the velocity, using these equivalents and
The angular acceleration the time rate of change of the angular speed according to:
Where is the original velocity, in the case the velocity before starting the deceleration, and is the final velocity, equal to zero because it has stopped.
b) To find the distance traveled in radians use the formula:
To change this result to inches, solve the angular displacement for the distance traveled ( is the radius).
c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:
The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):