A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards. The object encounters 3.29-N of friction. Determine t
he acceleration of the object.
1 answer:
Answer:
Explanation:
We will use the equation F - f = ma, which is just a fancy way of stating Newton's 2nd Law. For us:
F = 5.20 to the right (+)
f = 3.29 to the left (-)
m = 1.05 kg. Therefore,
5.20 - 3.29 = 1.05a and
1.91 = 1.05a so
a = 1.82 m/s/s to the right
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