Explanation:
In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.
Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.
For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.
Based on the sped of the waves and the tension as well as the needed wave speed, the required tension is 13.5 N.
<h3>What is the required tension?</h3>
Given the initial tension and speed, the tension that is required can be found by the formula:
= Initial tension x (Required speed / Initial speed)²
Solving gives:
= 6 x (30 / 20)²
= 6 x 9/4
= 13.5 N
In conclusion, the tension required is 13.5N.
Find out more on the tension on a wire at brainly.com/question/14290894.
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<span>The moon's gravitational pull causes: currents tides.</span>
The photosystem channels the excitation energy gathered by absorption of light by any one of the pigment molecules to a specific "reaction center chlorophyll," which in turn passes the energy to
-photosystem I.
-photosystem II.
-the primary electron acceptor.
-the secondary electron center.
-cytochrome.
Answer: -the primary electron acceptor.
Explanation:
The photosystem II has a reaction center, in the reaction center the energy from sunlight is converted into high energy electrons. At the center of the reaction center, chlorophyll molecule is present which absorbs the light and one of its electron is promoted to the higher energy.
The high energy electron is hop downward and it is transferred to the plastoquinone A, which is a primary electron acceptor. Then the electron is transferred to the plastoquinone B. The plastoquinone B will receives enough electrons it delivers its electron to the electron transfer chain.
Answer:
v = 7.32 m/s
Explanation:
The potential energy will convert to kinetic energy
½Iω² + ½mv² = mgh
Iω² + mv² = 2mgh
(½mR²)(v/R)² + mv² = 2mgh
½mv² + mv² = 2mgh
½v² + v² = 2gh
3v²/2 = 2gh
v² = 4gh/3
v² = 4(9.81)(4.10)/3
v² = 53.628
v = 7.323114...
v = 7.32 m/s
