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3 years ago

A compound has the empirical formula CH2O. If its molar mass is 150 g/mol, what is the molecular formula of the compound?

Chemistry

1 answer:

IgorLugansk [536]3 years ago

8 0

Answer:

C5H10O5

Explanation:

The molecular formula is a multiple of the empirical formula. I.e

Molecular formula => [CH2O]n

[CH2O]n = 150

[12 + (2x1) + 16 ]n = 150

30n = 150

Divide both side by the coefficient of n i.e 30

n = 150/30 = 5

Molecular formula => [CH2O]n

Molecular formula => [CH2O]5

Molecular formula => C5H10O5

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1. How much heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C?

diamong [38]

Answer: An amount of $40980.48 J/g^{o}C$ heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

Explanation:

Given: mass of lead = 4.64 kg

Convert kg into grams as follows.

$1 kg = 1000 g\\4.64 kg = 4.64 kg \times \frac{1000 g}{1 kg}\\= 4640 g$

$T_{1} = 150^{o}C$

$T_{2} = 219^{o}C$

The standard value of specific heat of lead is $0.128 J/g^{o}C$ .

Formula used to calculate heat is as follows.

$q = m \times C \times \Delta T$

where,

q = heat energy

m = mass of substance

C = specific heat of substance

$\Delta T$ = change in temperature

Substitute the value into above formula as follows.

$q = m \times C \times \Delta T\\= 4640 g \times 0.128 J/g^{o}C \times (219 - 150)^{o}C\\= 40980.48 J/g^{o}C$

Thus, we can conclude that $40980.48 J/g^{o}C$ heat is required to raise the temperature of 4.64kg of lead from 150°C to 219°C.

8 0

3 years ago

A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

The final temperature is 407.57 K

7 0

3 years ago

If smelly suzy has 109 scrunchies and 47 visco stickers for her hydroflasksksksksks hiw many visco items does she have in total

andreyandreev [35.5K]

Answer:

156

Explanation: SKSKSKSKSKSKKSKSKSKSKKS

6 0

3 years ago

\al(s) + 3agno3(aq) → al(no3)3(aq) + 3ag(s) this equation represents which type of chemical reaction?

Savatey [412]

Al(s) + 2AgNO3(aq) = Al(NO3)3(aq) + 3 Ag (s)

is a single replacement reaction

A single replacement reaction is a type of chemical reaction were element react with a compound and the element take place of another element in that compound. In the reaction above Aluminium (Al) take the place of silver (Ag) from it compound.that is AgNO3. single replacement reaction is possible because aluminium is in high in reactivity series as compared to silver.

3 0

3 years ago

in a titration 5.0 mL of a 2.0 M NaOH(aq) solution exactly neutralizes 10.0 mL of an HCI(aq) solution. What is the concentration

Hitman42 [59]

Volume of base(NaOH)= Vb =5 mL
Concentration of base(NaOH)= Mb =2 M
Volume of acid(HCl)= Va =10 mL
Concentration of acid(HCl)= Ma = ?
Now,
Ma*Va = Mb*Vb
Ma*(10) = (2)*(5)

Ma= 1M

7 0

4 years ago