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Oksi-84 [34.3K]
3 years ago
14

Making positive lifestyle choices will __________.

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
3 0
Benefit you and your life in many ways!
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Meteorologists use weather balloons to carry weather instruments high into the atmosphere. When it is first released at Earth’s
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The pressure of the gas used in the weather balloon increases to expand the balloon.

Explanation:

  • Weather balloons contain the boxes where the weather measurement instruments are present that is attached to the large balloon.
  • Weather balloon uses gases like Hydrogen or Helium. When the weather balloon rises to the atmosphere, the air pressure decreases. This leads to the increase in the pressure of hydrogen or Helium gas used in the weather balloon. This expands the balloon.
  • The gas particles hits the balloon container and generates the pressure. The increase of pressure thus helps the weather balloon to move in a constant speed through the atmosphere.
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Which statement explains how the Sun influences movement in the Earth's atmosphere?
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Correct Answer: The Sun heats the Earth unevenly; this heating pattern then causes convection currents in the atmosphere.
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True/False: Animal embryos look similar early in development because all animals share a common ancestor.
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The normal boiling point of a liquid is 282 °C. At what temperature (in
ElenaW [278]

Answer:

The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C

Explanation:

Here we make use of the Clausius-Clapeyron equation;

ln\left (\frac{p_{2}}{p_{1}}  \right )=-\frac{\Delta H_{vap}}{R}\cdot \left (\frac{1}{T_{2}}-\frac{1}{T_{1}}  \right )

Where:

P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K

P₂ = 0.2 atm = The substance vapor pressure at temperature T₂

\Delta H_{vap} = The heat of vaporization = 28.5 kJ/mol

R = The universal gas constant = 8.314 J/K·mol

Plugging in the above values in the Clausius-Clapeyron equation, we have;

ln\left (\frac{0.2}{1}  \right )=-\frac{28.5 \times 10^3}{8.3145}\cdot \left (\frac{1}{T_{2}}-\frac{1}{555.15}  \right )

\therefore T_2 = \frac{-3427.95}{ln(0.2)-6.175}

T₂ = 440.37 K

To convert to Celsius degree temperature, we subtract 273.15 as follows

T₂ in °C = 440.37 - 273.15 = 167.22 °C

Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.

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3 years ago
What is the volume in ML
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