Answer:
E) The object achieves its maximum speed at approximately x=3m.
Explanation:
Since the object is moving in gravitational field
potential energy + kinetic energy = constant = 14 J
At x = 3 m , potential energy is minimum that is zero
kinetic energy will be maximum .
Kinetic energy = 14 - 0 = 14 J
Hence option ( E ) is the answer.
Initial velocity (u) = 2 m/s
Acceleration (a) = 10 m/s^2
Time taken (t) = 4 s
Let the final velocity be v.
By using the equation,
v = u + at, we get
or, v = 2 + 10 × 4
or, v = 2 + 40
or, v = 42
The final velocity is 42 m/s.
Object Falling from Rest. As an object falls from rest, its gravitational potential energy is converted to kinetic energy. Conservation of energy as a tool permits the calculation of the velocity just before it hits the surface. K.E. = J, which is of course equal to its initial potential energy.
Answer:
v = 34.128 km/hr
Explanation:
Given that,
The initial speed of a truck, u = 0
Acceleration of the truck, a = 0.3 m/s²
Distance moved, d = 150 m
Let the final speed of the truck is v. Using third equation of motion i.e.
Put all the values,
or
v = 34.128 km/h
So, the final speed of the truck is equal to 34.128 km/h.
