Answer:
Q must be placed at 0.53 L
Explanation:
Given data:
q_1 = 4.0 μC , q_2 = 3.0μC
Distance between charge is L
third charge q be placed at distance x cm from q1
The force by charge q_1 due to q is
----1
The force by charge q_2 due to q is
--2
we know that net electric force is equal to zero
F_1 = F_2
x = 0.53 L
Q must be placed at 0.53 L
The distance from the base of the building the rock will land is 26.4 m
<h3>Data obtained from the question </h3>
- Horizontal velocity (u) = 20 m/s
- Height (h) = 8.50 m
- Distance (s) =?
<h3>Determination of the time to reach the ground </h3>
- Height (h) = 8.50 m
- Acceleration due to gravity (g) = 9.8 m/s²
- Time (t) =?
h = ½gt²
8.5 = ½ × 9.8 × t²
8.5 = 4.9 × t²
Divide both side by 4.9
t² = 8.5 / 4.9
Take the square root of both side
t = √(8.5 / 4.9)
t = 1.32 s
<h3>How to determine the distance </h3>
- Horizontal velocity (u) = 20 m/s
- Time (t) = 1.32 s
- Distance (s) =?
s = ut
s = 20 × 1.32
s = 26.4 m
Learn more about motion under gravity:
brainly.com/question/22719691
Answer:
The equation of motion is derived based on the Newton’s laws of motion. And it changes accordingly when an object changes with uniform velocity.
Given is that object moves with uniform velocity, that is no change in velocity so there will no acceleration.
As we know
Here, u = v (due to uniform velocity)
.
1st equation of motion is, v = u + at
2nd equation of motion,
3rd equation of motion,
.
Explanation:
Answer:
resultant is a single force that can replace the of a number of forces , equililbrant is a force that is exactly opposite to resultant
Explanation:
