it can with stand certain pressure inside, once it exceeds the pressure will be released by making a whistle....... hence it wont burst
The volume of acetone, in milliliters, has a mass of 44.2 g is 55.96mL.
<h3>HOW TO CALCULATE VOLUME?</h3>
The volume of a substance can be calculated by dividing the mass by its density. That is;
Volume (mL) = mass (g) ÷ density (g/mL)
According to this question, acetone is a solvent with density of 0.7899g/mL and mass of 44.2g. The volume is calculated as follows:
Volume = 44.2g ÷ 0.7899g/mL
Volume = 55.96mL
Therefore, the volume of acetone, in milliliters, has a mass of 44.2g is 55.96mL.
Learn more about volume at: brainly.com/question/1578538
Answer:
∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.
Explanation:
- We can solve this problem using the general gas law:
<em>PV = nRT</em>, where,
P is the pressure of the gas <em>(atm)</em>,
V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,
n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,
R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,
T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).
∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.
- <em>Now, we should convert the pressure from (atm) to (kPa).</em>
1.0 atm → 101.325 kPa,
1.0135 atm → ??? kPa.
∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.
The bathtub of water would melt the most ice because it has a larger area
