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jonny [76]
3 years ago
5

What's the word used to describe the weight of precious stones.​

Physics
2 answers:
pychu [463]3 years ago
6 0

Answer:

Ahhhhhh ano wala dito ang answer

Ksenya-84 [330]3 years ago
4 0
The answer to your question is carat
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You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving
Alecsey [184]
<h2>The balloon is moving when it is halfway down the building at 20.78 m/s.</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 9.81 m/s²  

Displacement, s = 0.5 x 44 = 22 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 9.81 x 22

v² = 431.64

v = 20.78 m/s

Velocity at 22 m = 20.78 m/s

The balloon is moving when it is halfway down the building at 20.78 m/s.

7 0
3 years ago
A car has a mass of 550 kg. What is the weight of the car?
lozanna [386]
1212.54 is what 550 kgs is equal to the weight of the car
3 0
3 years ago
Read 2 more answers
Calculate the kinetic energy of a car of mass 800kg moving at 100 kmph.
valentina_108 [34]

Answer:

KE = 308642.02469136 J

4 0
3 years ago
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave?
Vedmedyk [2.9K]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

Velocity (V) = 40 m/s

Wavelength (\lambda) = 80 cm = 0.8 m

<h3>To Find:-</h3>

The frequency (F) of the wave.

<h2>Solution:-</h2>

We know,

\bf V \: = \: F \: × \: \lambda

40 = F × 0.8

F = \frac{40}{0.8}

F = 50

<h3>The frequency of the wave is <u>5</u><u>0</u><u> </u><u>H</u><u>z</u>. [Answer]</h3>
7 0
3 years ago
Two forces F1 and F2 are acting on a block of mass m=1.5 kg. The magnitude of
nika2105 [10]

Answer:

Explanation:

Component of force F₁ in right direction = F₁cos37

= 12 x cos37 = 9.58 N .

Component of force F₂ in  vertically upward direction = F₁sin37

= 12 x sin37 = 7.22 N .

a ) Let normal force be R

R + F₁sin37  = mg

R + 7.22 = 1.5 x 9.8 = 14.7

R = 7.48 N .

b )

Net force in horizontal direction = F₂ - F₁cos37

= F₂ - 9.58

This is equal to zero as body is moving with zero acceleration

F₂ - 9.58 = 0

F₂ = 9.58 N

c ) If body is moving with acceleration of 2.5 m /s² along the direction of F₂

F₂ - 9.58 = 1.5 x 2.5 = 3.75

F₂ = 13.33 N .

6 0
3 years ago
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