How does the density of protostars compare to other stars?

Chemistry

1 answer:

lorasvet [3.4K]2 years ago

5 0

Protostars are less dense than other stars.

Explanation:

Protostars are very young ‘stars’ made from hydrogen clouds that are beginning to coalesce and collapse under their weight. The hydrogen has not even begun fusing. Therefore, they are mainly made of hydrogen which is the lightest element in the universe.

Stars, however, have begun fusing hydrogen to other heavier elements like helium, carbon, oxygen, and iron. The elements are much heavier than hydrogen making other stars much denser than protostars.

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Methanol (ch3oh), also called methyl alcohol, is the simplest alcohol. it is used as a fuel in race cars and is a potential repl

erica [24]

Answer:

%age Yield = 51.45 %

Solution:

Step 1: Convert Kg into g

68.5 Kg CO = 68500 g CO

8.60 Kg H₂ = 8600 g

Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

CO + 2 H₂ → CH₃OH

According to Equation,

28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂

So,

68500 g CO will react with = X g of H₂

Solving for X,

X = (68500 g × 4 g) ÷ 28 g

X = 9785 g of H₂

It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to equation,

4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol

So,

8600 g H₂ will produce = X g of CH₃OH

Solving for X,

X = (8600 g × 32 g) ÷ 4 g

X = 68800 g of CH₃OH

Step 4: Calculate %age Yield

%age Yield = Actual Yield ÷ Theoretical Yield × 100

Putting Values,

%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100