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zhuklara [117]
3 years ago
11

The mass percentage of hydrochloric acid within a solution is 15.00%. given that the density of this solution is 1.075 g/ml, fin

d the molarity of the solution.
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Given the mass percentage of HCl solution = 15.00 %

This means that 15.00 g HCl is present in 100 g solution

Moles of HCl = 15.00 gHCl*\frac{1 mol HCl}{36.46 g HCl} =0.411molHCl

Density of the solution = 1.075 g/mL

Calculating the volume of solution from density and mass:

100 g *\frac{1mL}{1.075 g} =93.0 mL

Converting volume from mL to L:

93.0 mL * \frac{1 L}{1000 mL} =0.093 L

Calculating the molarity of HCl solution from moles and volume:

\frac{0.411 mol}{0.093 L} =4.42 mol/L

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Answer:

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Explanation:

Equation of the reaction:

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Number of moles of HCl = molar concentration × volume

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By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

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Mass of Na3PO4 = molar mass × number of moles

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Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

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