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zhuklara [117]
3 years ago
11

The mass percentage of hydrochloric acid within a solution is 15.00%. given that the density of this solution is 1.075 g/ml, fin

d the molarity of the solution.
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Given the mass percentage of HCl solution = 15.00 %

This means that 15.00 g HCl is present in 100 g solution

Moles of HCl = 15.00 gHCl*\frac{1 mol HCl}{36.46 g HCl} =0.411molHCl

Density of the solution = 1.075 g/mL

Calculating the volume of solution from density and mass:

100 g *\frac{1mL}{1.075 g} =93.0 mL

Converting volume from mL to L:

93.0 mL * \frac{1 L}{1000 mL} =0.093 L

Calculating the molarity of HCl solution from moles and volume:

\frac{0.411 mol}{0.093 L} =4.42 mol/L

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<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is _{53}^{131}\textrm{I}

<u>For b:</u> The isotopic representation of cesium is _{55}^{137}\textrm{Cs}

<u>For c:</u> The isotopic representation of strontium is _{38}^{52}\textrm{Sr}

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The isotopic representation of an atom is: _Z^A\textrm{X}

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  • <u>For a:</u>

We are given:

Number of neutrons = 78

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Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is _{53}^{131}\textrm{I}

  • <u>For b:</u>

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is _{55}^{137}\textrm{Cs}

  • <u>For c:</u>

We are given:

Number of neutrons = 52

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