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Naily [24]
3 years ago
9

All of the following EXCEPT the resistance of _________ demonstrate artificially selected resistance.

Chemistry
2 answers:
Allushta [10]3 years ago
7 0
The answer is power for the blank.  

Ahat [919]3 years ago
3 0

Answer:

C

Explanation:

The resistance of Antarctic fish to freezing, due to antifreeze proteins in their blood. This is the only answer choice where natural selection is working, and not artificial selection by human means.

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Calculate OH- given H3 O+ = 1.40 *10^-4 M
vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

pH = 3.85

pH + pOH =14

pOH = 14 - 3.85

pOH = 10.15

The OH- concentration from the pOH by the equation:

pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

[OH-]  = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.

8 0
3 years ago
Sprinter set in starting blocks at the beginning of a race rely on what kind of energy conversion
ale4655 [162]
They convert chemical potential energy (stored in muscle cells) to kinetic energy (running)
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3 years ago
A student conducts an experiment by placing a wooden stick in a cup of sugar solution. Over the next few weeks, sugar crystals f
Ipatiy [6.2K]

Answer: In order to be alive there must be cells present and since sugar does not contain cells it is not alive.

Explanation:

8 0
3 years ago
How many molecules are there in 0.50 moles chlorine?
mariarad [96]

Answer:

molecules Cl- = 3.01 E23 molecules

Explanation:

molecules Cl- = 0.50 mol CL- * ( 6.02 E23 molecules/ mol ) = 3.01 E 23 molecules

3 0
3 years ago
Read 2 more answers
HELPPP!!
lord [1]

Answer:

The anion at the end on the compound

Explanation:

to check whether a substance is soluble or not, you would find the anion at the end of the compound on a solubility chart and then see from there whether it is soluble or not

5 0
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