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mixer [17]
3 years ago
13

Which product will turn yellow when cabbage juice is added?

Chemistry
2 answers:
lianna [129]3 years ago
7 0
It’s letter C. Vinegar
xeze [42]3 years ago
5 0

Answer:

Its B

Explanation:

You might be interested in
An initial mixture of nitrogen gas and hydrogen gas is reacted in a rigid container at a certain temperature by the reaction At
anygoal [31]

Answer: [N2]₀ = 10M and [H2]₀ = 11M

Explanation: To calculate the initial concentration, you would have to set up an ICE table, which is an organized way of tracking known quantities or the ones you want to find. ICE stands for:

I is initial amount;

C is change in concentration;

E is for equilibrium concentration;

For the mixture,

       N2                       3H2                2NH3

I      [N2]₀                     [H2]₀                  0

C     - x                          -3x                 +2x

E     [N2]₀ - x =8      [H2]₀ - 3x =5       2x =4

With the product, we can find "x":

2x=4

x=2M

With x=2, find the concentrations:

[N2]₀ - x = 8

[N2]₀ = 10M

[H2]₀ - 3x = 5

[H2]₀ = 11M

The initial concentrations of nitrogen gas [N2] is 10.0 M and of hydrogen gas [H2] is 11.0 M.

8 0
3 years ago
Read 2 more answers
PLS HURYYY ILL GIVE BRAINLIEST
ad-work [718]

The volume increases when the balloon temperature increases.

<u>Explanation:</u>

-10 F is converted into Kelvin as 249 K.

0°C is nothing but 0+ 273 = 273 K

And the room temperature is 25°C which is converted into Kelvin as 273 + 25 = 298 K.

249 K is below room temperature.

As per the Charles' law volume and temperature are directly proportional to each other, when the pressure of the gas remains constant.

V ∝ T

As the balloon temperature increases, the volume also increases.

5 0
3 years ago
How many mL of 0.013 M potassium hydroxide are required to reach the equivalence point in the titration of 75 mL 0.166 M hydrocy
umka21 [38]

Answer:

957.7mL

Explanation:

Using the formula below;

CaVa = CbVb

Where;

Ca = concentration of acid (M)

Va = volume of acid (mL)

Cb = concentration of base (M)

Vb = volume of base (mL)

According to the information provided in this question:

Ca = 0.166 M

Cb = 0.013 M

Va = 75mL

Vb = ?

Using CaVa = CbVb

0.166 × 75 = 0.013 × Vb

12.45 = 0.013Vb

Vb =12.45/0.013

Vb = 957.7mL

6 0
3 years ago
in a given homologous series of hydrocarbons, the boiling point generally increases as the size of the molecules increases. the
vitfil [10]

The boiling point of hydrocarbons generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

<h3>What are hydrocarbons?</h3>

Hydrocarbons are organic compounds which here composed of hydrogen and carbon alone.

Hydrocarbons are grouped into families or homologous series based on a reactive group known as the gincyiial group

The homologous series include

  • alkanes
  • alkenes
  • alkynes

The boiling point generally increases as the size of the molecules increases because more bonds are needs to be broken in larger organic molecules.

Learn more about hydrocarbons at: brainly.com/question/3551546

#SPJ1

5 0
2 years ago
Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce
adoni [48]

Answer:

The answer is "10.84 g".

Explanation:

The formula for calculating the number for moles:

\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }

In the given acid nitric:

Owing to the nitric acid mass = 75.9 g

Nitric acid molar weight= 63\  \frac{g}{mol}

If they put values above the formula, they receive:

\text{moles in nitric acid} = \frac{75.9}{63}

                               =1.204 \ mol

In the given chemical equation:

3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.

So, 1.204 moles of nitric acid will be produced:

= \frac{1}{2} \times 1.204

=0.602\ \ \text{mol of water}.

We are now using Equation 1 in determining the quantity of water:

Water moles = 0.602\  mol

Water weight molar = 18.02 \ \frac{g}{mol}

\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\

                         =10.84 \ g

8 0
3 years ago
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