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ExtremeBDS [4]
2 years ago
6

Suppose you want to calculate how much work it

Physics
1 answer:
Jobisdone [24]2 years ago
6 0

Mass is not necessary the main thing we need is Displacement

As

  • W=FD

Or

  • Work done=Force×Displacement

The amount of work done is calculated as the force exerted to remove a object to D distance .

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Speed is velocity in a given direction<br> O True<br> O False
Zarrin [17]

Answer:

FALSE

Explanation:

Velocity = speed with direction.

Think of speed and direction like rockets and missiles. Rockets are not smart. Missiles are smart. Rockets go in one direction. Missiles can track their targets, they have a specific destination, a specific direction.

Velocity is often used in physics, because its almost useless to know how fast an object is going if you don't know which direction it is going.

Think of it like this. If the Weather man told you a hurricane was traveling at 30 miles an hour, but didn't tell you which direction it was going, you would have no idea where to run, or if it was going to hit you at all. However, if he told you it was going 30 miles an hour to the North, and you were West of it, you would be fine, and wouldn't have to worry.

8 0
3 years ago
Read 2 more answers
Long periods of unusually low precipitation are called?
DiKsa [7]
I think it is called a drought but i would look it up
6 0
3 years ago
Imagine standing on a bathroom scale and reading your weight. now lift one foot and read your weight again. does the scale read
7nadin3 [17]
Less because now there is less force on the scale and you are unbalanced. Therefore the scale will have a lower number then before.

8 0
3 years ago
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Manufactured bolts can’t be too long or too short or they might not fit where they need to. Help determine which bolts will work
Sever21 [200]
What is the longest the bolt can be and still be acceptable
5 0
3 years ago
Planets are not uniform inside. Normally, they are densest at the center and have decreasing density outward toward the surface.
SSSSS [86.1K]

Answer:

a = 9.94 m/s²

Explanation:

given,

density at center= 1.6 x 10⁴ kg/m³

density at the surface = 2100 Kg/m³

volume mass density as function of distance

\rho(r) = ar^2 - br^3

r is the radius of the spherical shell

dr is the thickness

volume of shell

dV = 4 \pi r^2 dr

mass of shell

dM = \rho(r)dV

\rho = \rho_0 - br

now,

dM = (\rho_0 - br)(4 \pi r^2)dr

integrating both side

M = \int_0^{R} (\rho_0 - br)(4 \pi r^2)dr

M = \dfrac{4\pi}{3}R^3\rho_0 - \pi R^4(\dfrac{\rho_0-\rho}{R})

M = \pi R^3(\dfrac{\rho_0}{3}+\rho)

we know,

a = \dfrac{GM}{R^2}

a = \dfrac{G( \pi R^3(\dfrac{\rho_0}{3}+\rho))}{R^2}

a =\pi RG(\dfrac{\rho_0}{3}+\rho)

a =\pi (6.674\times 10^{-11}\times 6.38 \times 10^6)(\dfrac{1.60\times 10^4}{3}+2.1\times 10^3)

a = 9.94 m/s²

7 0
3 years ago
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