Answer:
N₂=20.05 rpm
Explanation:
Given that
R= 19 cm
I=0.13 kg.m²
N₁ = 24.2 rpm

ω₁= 2.5 rad/s
m= 173 g = 0.173 kg
v=1.2 m
Initial angular momentum L₁
L₁ = Iω₁ - m v r ( negative sign because bird coming opposite to motion of the wire motion)
Final linear momentum L₂
L₂= I₂ ω₂
I₂ = I + m r²
The is no any external torque that is why angular momentum will be conserve
L₁ = L₂
Iω₁ - m v r = I₂ ω₂
Iω₁ - m v r = ( I + m r²) ω₂
Now by putting the all values
Iω₁ - m v r = ( I + m r²) ω₂
0.13 x 2.5 - 0.173 x 1.2 x 0.19 = ( 0.13 + 0.173 x 0.19²) ω₂
0.325 - 0.0394 = 0.136 ω₂
ω₂ = 2.1 rad/s

N₂=20.05 rpm
Ag on the periodic table is silver.
The atomic number for silver is 47, atomic symbol is Ag, and the atomic weight is 107.9.
The cheat was is to punch it in a calculator and multiply the answer by 100. But let's actually figure it out.
Get the denominator to a factor of 100.
The most convenient one for this is 5, since that's also a factor of 15.
Reduce the fraction with 3/3 (divide both the numerator and denominator by 3, in case that's unclear), and you get 3/5.
Multiply both by 20, and you get 60/100.
60%
Answer:
The rate of deceleration is 15 km/h^2.
Explanation:
Since the car comes in 90km/h, it will need deceleration for 15 km/h for 6 seconds to finally stop the car. 15*6=90