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2 years ago

PLEASE HELP WITH THIS QUESTION!!!!

2 answers:

8 0

The combined weight of all the samples can simply be calculated by the arithmetic sum of all the individual weights of each sample.

The total combined weight of all the samples is "114.22 lb".

Adding the individual weights of each sample we get:

Combined weight = Weight of sample 1 + Weight of sample 2 + Weight of sample 3

Combined Weight = 31.2 lb + 38.02 lb + 45 lb

Combined Weight = 114.22 lb

The attached picture shows weight addition.

Learn more about combined weight here:

brainly.com/question/22890217?referrer=searchResults

solniwko [45]2 years ago

3 0

Answer:

31,2 + 38,02 + 45 = 114.22lbs

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3. What is the main difference between a physical change and a chemical

Lana71 [14]

Answer:

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Consider two rods of the same length and diameter,

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3 years ago

If wave A has twice the amplitude and three times the frequency as wave B, then the energy carried by wave A must be ____ times

soldier1979 [14.2K]

Answer:

4 times

Explanation:

As we know that the energy of a wave is directly proportional to the square of the amplitude of the wave,

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3 years ago

Who much force is needed to accelerate a 68 kilogram-skier at a Rate of 1.2 m/sec

liberstina [14]

If F =m*a
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7 0

3 years ago

Anyone.... help with this two questions...

PSYCHO15rus [73]

Answer:

what is the question

]

Explanation:

7 0

2 years ago

Read 2 more answers

1/012=1/0.05+1/d' hiiiiiiiiii

klasskru [66]

Correct question is;

1/0.12 = (1/0.05) + (1/d')

Answer:

d' = -1/700

Explanation:

1/0.12 = (1/0.05) + (1/d')

Let's rearrange to get;

(1/d') = (1/0.12) - (1/0.05)

(1/d') = (1/(12/100)) - (1/(5/100))

(1/d') = 100/12 - 100/5

Let's multiply through by 60 to get rid of the denominators on the right side;

> (1/d') = 500 - 1200

> (1/d') = -700

> d' = -1/700

8 0

2 years ago