1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
storchak [24]
3 years ago
10

May someone help me with these questions it is only 2

Chemistry
1 answer:
garri49 [273]3 years ago
6 0
Most likely decreased birth rate and increased emigration.
You might be interested in
A mixture of methanol and methyl acetate contains 15.0 wt% methanol.
Usimov [2.4K]

The mixture flow rate in lbm/h = 117.65 lbm/h

<h3>Further explanation</h3>

Given

15.0 wt% methanol

The flow rate of the methyl acetate :100 lbm/h

Required

the mixture flow rate in lbm/h

Solution

mass of methanol(CH₃OH, Mw= 32 kg/kmol) in mixture :

\tt 15\%\times 200~kg=30~kg\\\\mol=\dfrac{mass}{MW}=\dfrac{30~kg}{32~kg/kmol}=0.9375~kmol

mass of the methyl acetate(C₃H₆O₂,MW=74 kg/kmol,85% wt) in 200 kg :

\tt 85\%\times 200=170~kg\\\\mol=\dfrac{170}{74}=2.297~kmol

Flow rate of the methyl acetate in the mixture is to be 100 lbm/h.

1 kg mixture = 0.85 .methyl acetate

So flow rate for mixture :

\tt \dfrac{1~kg~mixture}{0.85~methyl~acetat}\times 100~lbm/h=117.65~lbm/h

5 0
3 years ago
Given the ion C2O4-2, what species would you expect to form with each of the following ions?
Ksivusya [100]

Answer:

A. K₂C₂O₄          Potassium oxalate

B. CuC₂O₄          Copper oxalate

C. Bi₂(C₂O₄)₃         Bismuth (III) oxalate

D. Pb(C₂O₄)₂         Lead (IV) oxalate

E. (NH₄)₂C₂O₄       Ammonium oxalate

F. HC₂O₄⁻             Acid oxalate

Explanation:

C₂O₄⁻²  → oxalate anion

This is the conjugate base from the H₂C₂O₄ which is the oxalic acid. A weak dyprotic acid that can release 2 protons.

A. 2K⁺  +  C₂O₄⁻²  → K₂C₂O₄          Potassium oxalate

It can be formed by the neutralization of the acid with the base

H₂C₂O₄  + 2KOH  → K₂C₂O₄  +  2H₂O

B. Cu²⁺ +  C₂O₄⁻²   ⇄  CuC₂O₄  ↓

This is a precipitate.

C.  2Bi³⁺  +  3C₂O₄⁻²   ⇄  Bi₂(C₂O₄)₃  ↓

This is a precipitate.

D.  Pb⁴⁺ +  2C₂O₄⁻²   ⇄  Pb(C₂O₄)₂  ↓

This is a precipitate.

E. 2NH₄⁺  +  C₂O₄⁻²   ⇄  (NH₄)₂C₂O₄  ↓

This is a precipitate.

F. This is the conjugate strong base, for the weak acid

H⁺  +  C₂O₄⁻²   ⇄  HC₂O₄⁻

HC₂O₄⁻  + H₂O  ⇄  C₂O₄⁻²  +  H₃O⁺    Ka

HC₂O₄⁻  + H₂O  ⇄  H₂C₂O₄  +  OH⁻    Kb

HC₂O₄⁻  is an amphoteric compound

6 0
3 years ago
What happens to the rate of reaction when you decrease the temperature of a chemical reaction?
Neporo4naja [7]
Depending on what chemicals you use it slows the reaction
4 0
3 years ago
Read 2 more answers
Calculate 5+7*3*<br><br> Your answer:​
Mrac [35]
I got the answer 26
I’m confused what the star after the 3 is

hoped this helped:)
5 0
3 years ago
Read 2 more answers
Why do atoms exchange or share electrons during bonding
kondaur [170]

Answer:

Because it gives them a full valence shell.

Explanation:

5 0
2 years ago
Other questions:
  • Name: Date:
    11·1 answer
  • Calculate the volume of dry co2 produced at body temperature (37 ∘c) and 0.960 atm when 24.0 g of glucose is consumed in this re
    7·1 answer
  • : 0.882 mm what’s the answer
    13·2 answers
  • For the reaction A (g) → 3 B (g), Kp = 80100 at 298 K. When ∆G = -14.2 kJ/mol, what is the partial pressure of A when the partia
    13·1 answer
  • HELP PLEASE I DONT KNOW WHAT THIS MEANS IM CONFUSED
    7·1 answer
  • What occurs to the atoms of reactants in a chemical reaction?
    8·1 answer
  • What is the mass of 4.5 moles of sodium fluoride?
    14·1 answer
  • Milk of Magnesia is a type of medication people can take to help with heartburn and indigestion cause by stomach acid.
    15·1 answer
  • student conducted a simple experiment to explore heat transfer they constructed the closed system you see here a metal soda can
    6·1 answer
  • If there was a drink that could make you younger, how much would you drink from the bottle? If for one drink you become 1 year y
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!