Ask question

Ask question

All categories

3 years ago

15

Calculate the noise voltage spectrum Su(f) on a paraller RC circuit with R=1 kOhm and C=1 nF. (Don't forget to provide the unit!

) (3 points) - How much it is at 1 Hz ?

1 answer:

ladessa [460]3 years ago

3 0

Answer: 10^-3 V^2/Hz

Explanation:

1 Hz:

Su(f) = No * |H(f)|^2

= 10^-3 * 1/(1+(2*pi*f*R*C)^2)

= 10^-3 V^2/Hz

You might be interested in

Random errors can be reduced by taking repeated measurements.Error and uncertainty are interchangeable words that describe the s

fiasKO [112]

repeated mesurement can reduce the error

it is true

if you take any mesurement repeatedly and the average is taken, the error will be less

5 0

1 year ago

What type of data allows geologists to know what rock layers lie underneath Minnesota?

mrs_skeptik [129]

The answer is well log data, it is a detailed log of information taken from a borehole which geologist used to study geological formations of the earth's layer taken from samples returned from the borehole which was dugged.

5 0

3 years ago

Which statement best describes metallic bonding

horrorfan [7]

Answer:

It's a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal bars. It can also be described as the sharing of free electrons among a structure of positively charged ions

4 0

3 years ago

3 + 2 ∙ 4 = 3 + (2 ∙ 4)

Rzqust [24]

Answer:

11 = 11

Explanation:

6 0

3 years ago

Read 2 more answers

Tamsen is interested in history, and read that because of its regular period, the pendulum constituted the basis of the most acc

geniusboy [140]

We will apply the concept of period in a pendulum, defined as the product between 2 $\pi$ by the square root of the length over gravity, this is mathematically

$T = 2\pi \sqrt{\frac{L}{g}}$

Here,

T = Period

L = Length

g = Acceleration due to gravity

For the period to be 1 second, then we must look for the necessary length for such a requirement so

$1 = 2\pi \sqrt{\frac{L}{9.8}}$

$(\frac{1}{2\pi})^2 = \frac{L}{9.8}$

$L = 9.8(\frac{1}{2\pi})^2$

$L = 0.2482m$

The meter's length would be slight less than one-fourth of its current length. Also, the number of significant digits depends only on how precisely we know g, because the time has been defined to be exactly 1s.

Therefore the correct answer is C.

3 0

3 years ago