Answer:
0.0933 moles/Litre
Explanation:
We assume that the number of moles of N- used is equal to the number of moles of Nitrogen containing compounds that are generated due to the fact that the nitrogen containing compound that are produced contain only one nitrogen in each atom. As such, finding the amount of nitrogen used up explains the amount of compound formed. This can be expressed as follows:
Energy cost = 
Given that:
Energy = 100 W for 60 minutes
100 W = 100 J/s
= 100 J/s × (60 × 60) seconds
= 3.6 × 10⁵ J
Let now convert 3.6 × 10⁵ J to eV; we have:
= ( 3.6 × 10⁵ × 6.242 × 10¹⁸ )eV
= 2.247 × 10²⁴ eV
So, number of N-atom used up to form compounds will now be:
= 2.247 × 10²⁴ eV × 
= 1.123 × 10²³ N-atom
To moles; we have:
= 
= 0.186 moles
However, we are expected to leave our answer in concentration (i.e in moles/L)
since we are given 2L
So; 0.186 moles ⇒ 
= 0.0933 moles/Litre
Answer: 385.4132857
Explanation:
Using the equation, PV=nRT, you can solve this problem.
P= 3.5 kPa V=? n= 0.55 moles of air T= 295K R= 8.314 (L kPa/mol K)
We use the constant rate of <u>8.314</u> because we are using kilopascals in this problem.
Using simple algebra we get-
V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa
Using the calculator, we would get the answer of 385.4132857 L.
And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.
If you cross a heterozygous organism with another heterozygous organism, pair two Tt and Tt. Below is a punnet square to show the result:
T t
T TT Tt
t Tt tt
This means that you have two heterozygous recessive and one homogenous dominant and one homogenous recessive.