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Sloan [31]
2 years ago
10

In astronomy, distances are often expressed in light-years. One light-year is the distance traveled by light in one year. If the

distance to a star is 3.6 light-years, what is this distance in meters? (There are 365.25 days in one year.)
Physics
1 answer:
tatuchka [14]2 years ago
4 0

Answer:

The distance of the star is 3.40x10^{16} meters

Explanation:

It is known that the speed of light has a value of 3x10^{8}m/s in vacuum. That is, it travels 3x10^{8]m in one second, according with the following equation:    

v = \frac{x}{t}

Where v is the speed, x is the distance and t is the time.

x = v\cdot t (1)

Equation 1 can be used to determine the distance that the light travels in 1 year:  

It is necessary to find how many seconds are in 1 year (365.25 days).

365.25 days \cdot \frac{86400s}{1 day}  ⇒  31557600s

           

x = (3x10^{8}m/s)(31557600s)    

x = 9.46x10^{15}m      

Therefore, in 1 year, light travels 9.46x10^{15} meters.

<em>If the distance to a star is 3.6 light-years, what is this distance in meters?  </em>

A simple conversion between units can be used to get the distance in meters

x_{star} = 3.6ly \cdot \frac{9.46x10^{15}m}{1ly}<em> ⇒ </em>3.40x10^{16}m

Hence, the distance of the star is 3.40x10^{16} meters.              

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Bella makes the 6.1m distance to her food bowl in 8.8 seconds what is her average velocity
storchak [24]
Bella’s average velocity is about 0.693 meters per second.

To find the average velocity, you must divide the distance by the change in time, which should look like v=d/t

Here is how you set up the equation-
v=6.1/8.8

Once you divide 6.1 meters by 8.8 seconds, you should get a number that looks like 0.69318182.... however, I just rounded it to 0.693 meters per second. You can round it to whatever you like.

Hope this helped! If you have any questions about what I mentioned in my answer or explanation, feel free to comment on my answer and I’ll try to get back to you!
8 0
2 years ago
The value of acceleration due to gravity is less at the top of Mount Everest then that in the terai reason, why?​
xxTIMURxx [149]

Answer:

The value of acceleration due to gravity is greater in terai than in mountain. In terai region the radius of earth is less as it lies close to the centre of the earth. Thus, the value of g is more in terai region.

3 0
2 years ago
Find the hiker’s gravitational potential energy if the cliff is 60m high
Furkat [3]

Answer:

Potential energy is U=mgh

Explanation:

The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.

Potential energy  U=mgh

In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.

But we know the values of g and h

g=9.81m/s^2

h=60m

So, the potential energy

U=m(9.81m/s^2)(60m)\\\\U=588.6*m

m is the mass of the hiker, wich is not in the description of the problem.

4 0
2 years ago
A 2. 0 μf and a 4. 0 μf capacitor are connected in series across an 8. 0-v dc source. what is the charge on the 2. 0 μf capacito
Nezavi [6.7K]

voltage across 2.0μf capacitor is 5.32v

Given:

C1=2.0μf

C2=4.0μf

since two capacitors are in series there equivalent capacitance will be

[tex] \frac{1}{c} = \frac{1}{c1} + \frac{1}{c2} [/tex]

c =  \frac{c1 \times c2}{c1 + c2}

=  \frac{2 \times 4}{2 + 4}

=1.33μf

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

Q=CV

given,V=8v

= 1.33 \times 10 {}^{ - 6}  \times 8

= 10.64 \times 10 {}^{ - 6}

charge on 2.0μf capacitor is

\frac{Qeq}{2 \times 10 {}^{ - 6} }

=  \frac{10.64 \times 10 {}^{ - 6} }{2 \times 10 {}^{ - 6} }

=5.32v

learn more about series capacitance from here: brainly.com/question/28166078

#SPJ4

3 0
1 year ago
A wave has a velocity of 24 m/s and a period of 3.0 s. Calculate the wavelength of the wave.
Katyanochek1 [597]

Velocity (unit:m/s) of the wave is given with the formula:

v=f∧,

where f is the frequency which tells us how many waves are passing a point per second (unit: Hz) and ∧ is the wavelength, which tells us the length of those waves in metres (unit:m)

f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

5 0
2 years ago
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