I think it’s 6,9,16 for the answer
Answer:
63 girls.
Step-by-step explanation:
45 boys divided by 5= 9
9x7= 63 girls
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
f = -
Step-by-step explanation:
Given f varies directly with m then the equation relating them is
f = km ← k is the constant of variation
To find k use the condition f = - 19 when m = 14
- 19 = 14k ( divide both sides by 14 )
- = k
f = - m ← equation of variation
When m = 2 , then
f = - × 2 = -
Answer:
It is
5/7
Explanation:
The number
5/7
tells you that when
x
increases of
1
then
y
always increases of
5/7
.
Graphically:
graph{7/7*x [-10, 10, -5, 5]}
Step-by-step explanation: