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shusha [124]
3 years ago
12

You are given a cylinder of outer radius 3.27 cm and length of 11.5 cm. along the axis of the cylinder is a hole of diameter 2.4

7 cm. find the volume of this cylindrical shell.
Physics
1 answer:
natta225 [31]3 years ago
7 0
  <span> Required Volume (V) = Area of the base * Height

Area of the base = Pi [ 3.27² - (2.47/2)² ] since 2.47 is diameter and not radius. = Pi ( 9.981675 )

Therefore Volume (V) = Pi ( 9.981675) * 15.9 = 498.5978739 cm³ = 498.6 cm³.</span>
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An earthquake is a natural rapid shaking of the _______ caused by the release of stored energy in rocks
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Answer:

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dybincka [34]

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5 0
2 years ago
In a double-slit experiment, light from two monochromatic light sources passes through the same double slit. The light from the
MatroZZZ [7]

Answer:

The wavelength is \lambda_2 =  534 *10^{-9} \ m

Explanation:

From the question we are told that

   The wavelength of the first light is  \lambda _ 1 =  587 \ nm

    The order of the first light that is being considered is  m_1  =  10

     The order of the second light that is being considered is  m_2  =  11

Generally the distance between the fringes for the first light is mathematically represented as

      y_1 =  \frac{ m_1  * \lambda_1 *  D}{d}

 Here  D is the distance from the screen

 and    d  is the distance of separation of the slit.

      For the second light the distance between the fringes is  mathematically represented as

         y_2 =  \frac{ m_2  * \lambda_2 *  D}{d}

Now given that both of the light are passed through the same double slit

       \frac{y_1}{y_2}  =  \frac{\frac{m_1 *  \lambda_1 * D}{d}  }{\frac{m_2 *  \lambda_2 * D}{d}  } = 1

=>    \frac{ m_1 *  \lambda _1  }{ m_2  *  \lambda_2} =  1

=>     \lambda_2 =  \frac{m_1 *  \lambda_1}{m_2}

=>    \lambda_2 =  \frac{10  *   587 *10^{-9}}{11}

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