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Andrei [34K]
3 years ago
13

A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket

. The bolt hits the ground 6.10s later. What was the rocket's acceleration?
Physics
1 answer:
Olenka [21]3 years ago
7 0

Answer:

1.3m/s²

Explanation:

Given values in the first part: acceleration a, time t₁:

1) velocity v₀ = at_1

2) height h₀ =\frac{1}{2}at_1^2

Given values in the second part: acceleration -g,  time t₂:

3) height h = -\frac{1}{2}gt_2^2+v_0t_2+h_0

Combining equations 1,2,3 and setting h to zero:

0=-\frac{1}{2}gt_2^2+(at_1)t_2+\frac{1}{2}at_1^2\\ 0=a(t_1t_2+\frac{1}{2}t_1^2)-\frac{1}{2}gt_2^2

Solve for a with t₁ = 4s and t₂=2.1s:

a=\frac{1}{2}gt_2^2(\frac{1}{t_1t_2+\frac{1}{2}t_1^2})

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What does an element’s molar mass tell you about the element?
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Answer:

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2 years ago
An upright object 2.80 cm tall is placed 16.0 cm away from the vertex of a concave mirror with a center of curvature of 24.0 cm.
horrorfan [7]

Answer:

f = 12 cm

Explanation:

<u>Center of Curvature</u>:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of  mirror.

<u>The Radius of Curvature</u>:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of  mirror. It is the distance from pole to the center of curvature.

<u>Focal Length</u>:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

f = \frac{R}{2}

where,

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R = Radius of curvature = 24 cm

Therefore,

f = \frac{24\ cm}{2}

<u>f = 12 cm</u>

8 0
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What would happen to a loop in a metal tube when it is heated
Galina-37 [17]
I think it most likely burn since th metal tube is going to transfer so much heat
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rusak2 [61]

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