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Julli [10]
1 year ago
11

Which situations are necessary components for malpractice to occur?

Physics
1 answer:
Yuri [45]1 year ago
3 0

a. The risk of injury must be predictable.

b. A "breach of duty" is when a professional fails to uphold a level of care.

c. There must be a standard of care in place, and the practitioner must assume responsibility for the patient.

d. There must be a clear link between the treatment received and the harm.

<h3>What is malpractice?</h3>

Malpractice, commonly referred to as professional negligence, is defined as "an incident of carelessness or incompetence on the part of a professional" under tort law.

The following professionals might be the target of malpractice claims:

Medical professionals: If a doctor or other healthcare practitioner does not exercise the level of care and competence that a similarly situated professional in the same medical field would deliver under the circumstances, a medical malpractice claim may be made against them.

Lawyers: Failure to provide services with the amount of competence, care, and diligence that a reasonable lawyer would use in the same situation may be grounds for a legal malpractice claim.

To know more about malpractice, visit;

brainly.com/question/25441985

#SPJ4

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Two people stand across from one another at the top edges of identical buildings, 50 meters above the ground. One person throws
cricket20 [7]

Answer:

C

Explanation:

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6 0
2 years ago
If a closed series circuit has a voltage of 12 V and R1 = 4 Ω and R2 = 2 Ω, what is the current running through R1 and R2?
Phantasy [73]
Total resistance=R1+ R2= 6Ω
Voltage=12v
Current =\frac{voltage}{resistance}
Current= 2A
In a series circuit, equal current passes through every resistance.
Answer is option A
7 0
2 years ago
car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of a. The car
Luba_88 [7]

Answer:

0.572

Explanation:

First examine the force of friction at the slipping point where Ff = µsFN = µsmg.

the mass of the car is unknown,

The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.

First the tangential direction

∑Ft =Fft =mat

And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r

Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2

So going backwards and plugging in Ffc =m2atπr/ 2r =πmat

Ff = √(F2ft +F2fc)= matp √(1+π²)

µs = Ff /mg = at /g √(1+π²)=

1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572

7 0
3 years ago
4. A high school athlete runs 400 m in 52.20 sec. What is his speed in mph?<br> 14100<br> 1110
Serggg [28]

Answer:

28,800m/p second

Explanation:

Calculate the distance per second so, 400m/50 s= 8m/p second now knowing the speed/hour and knowing an hour has 3,600 seconds,multiply it by 8 then you will get 28,800m/p second, or 28.8km/h

3 0
2 years ago
julia throws a ball vertically upward from the ground with a speed of 5.89m/s. Andrew catches it when it is on its way down at a
aliya0001 [1]
Vo = 5.89 m/s Y = 1.27 m g = 9.81 m/s^2 
Time to height 
Tr = Vo / g Tr = (5.89 m/s) / (9.81 m/s^2) Tr = 0.60 s 
Max height achieved is:
H = Vo^2 / [2g] H = (5.89 )^2 / [ 2 * (9.81) ] H = (34.69) / [19.62] H = 1.77 m 
It falls that distance, minus Andrew's catch distance:
h = H - Y h = (1.77 m) - (1.27 m) h = 0.5 m 
Time to descend is therefore:
Tf = √ { [2h] / g ] Tf = √ { [ 2 * (0.5 m) ] / (9.81 m/s^2) } Tf = √ { [ 1.0 m ] / (9.81 m/s^2) } Tf = √ { 0.102 s^2 } Tf = 0.32 s 
Total time is rise plus fall therefore:
Tt = Tr + Tf Tt = (0.60 s) + (0.32 s) Tt = 0.92 s           (ANSWER)
8 0
3 years ago
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