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1 year ago

Which situations are necessary components for malpractice to occur?

Physics

1 answer:

Yuri [45]1 year ago

3 0

a. The risk of injury must be predictable.

b. A "breach of duty" is when a professional fails to uphold a level of care.

c. There must be a standard of care in place, and the practitioner must assume responsibility for the patient.

d. There must be a clear link between the treatment received and the harm.

<h3>What is malpractice?</h3>

Malpractice, commonly referred to as professional negligence, is defined as "an incident of carelessness or incompetence on the part of a professional" under tort law.

The following professionals might be the target of malpractice claims:

Medical professionals: If a doctor or other healthcare practitioner does not exercise the level of care and competence that a similarly situated professional in the same medical field would deliver under the circumstances, a medical malpractice claim may be made against them.

Lawyers: Failure to provide services with the amount of competence, care, and diligence that a reasonable lawyer would use in the same situation may be grounds for a legal malpractice claim.

To know more about malpractice, visit;

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Given that y is the vertical displacement of a wave at anytime and A is the amplitude of the wave, w is the angular speed of the

denis-greek [22]

Explanation:

The general equation describing a wave is:

y(x,t) = A sin(kx - wt)

Let's say that for a particular wave on a string the equation is:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

(a) Determine the wave's amplitude, wavelength, and frequency.

(b) Determine the speed of the wave.

(d) Determine the direction of propagation of the wave.

(e) Determine the maximum transverse speed of the string.

Solutions

Part (a): The wave's amplitude, wavelength, and frequency can be determined from the equation of the wave:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

The amplitude is whatever is multiplying the sine.

A = 0.9 cm

The wavenumber k is whatever is multiplying the x:

k = 1.2 m-1The wavelength isl=2pk= 5.2 m

The angular frequency w is whatever is multiplying the t.

w = 5.0 rad/sf=w2p= 0.80 Hz

Part (b): The wave speed can be found from the frequency and wavelength:

v = f l = 0.80 * 5.2 = 4.17 m/s

Part (c): With m = 0.012 kg/m and the wave speed given by:v=(Tm)½

This gives a tension of T = m v2 = 0.012 (4.17)2 = 0.21 N.

Part (d): To find the direction of propogation of the wave, just look at the sign between the x and t terms in the equation. In our case we have a minus sign:

y(x,t) = (0.9 cm) sin[(1.2 m-1)x - (5.0 s-1)t]

A negative sign means the wave is traveling in the +x direction.

A positive sign means the wave is traveling in the -x direction.

Part (e): To determine the maximum transverse speed of the string, remember that all parts of the string are experiencing simple harmonic motion. We showed that in SHM the maximum speed is:

vmax = Aw

In this case we have A = 0.9 cm and w = 5.0 rad/s, so:

vmax = 0.9 * 5.0 = 4.5 cm/s

maybe this should help

6 0

3 years ago

A toboggan approaches a snowy hill moving at 11.7 m/s. The coefficients of static and kinetic friction between the snow and the

soldi70 [24.7K]

Answer:

The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

Explanation:

Given that,

Speed = 11.7 m/s

Coefficients of static friction = 0.48

Coefficients of kinetic friction = 0.34

Angle = 40.0°

(a). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta+\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40+0.34\times\cos40)$

$a=8.85\ m/s^2$

(b). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta-\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40-0.34\times\cos40)$

$a=3.74\ m/s^2$

Hence, The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

5 0

3 years ago

The student in item 1 moves the box up a ramp inclined at 12 degrees with the horizontal. If the box starts from rest at the bot

Alik [6]

Answer:

Acceleration up the ramp = -2.745 m/ $s^{2}$

Explanation:

Given

box is pulled at angle Θ = $25^{o}$

Force applied F = 185N

coefficient of friction, μ $_{k}$ = 0.27

mass of the box m = 35 kg

We know that,

acceleration due to gravity g = 9.8 m/ $s^{2}$

horizontal component $F_{x}$ = F cosΘ = 185 * cos $25^{o}$ =167.67

vertical component $F_{y}$ = F sinΘ =185*sin $25^{o}$ = 78.18

Another vertical component is due to gravity $F_{g}$ , force in given by

$F_{g}$ = mg

= 35 x 9.8

= 343.35 N

Normal force $F_{n}$ = $F_{g}$ - $F_{y}$

= 343.35 - 78.18

= 265.17 N

Frictional force $F_{k}$ = $F_{n}$ * μ $_{k}$

= 265.17 * 0.27

= 71.596 N

To find acceleration, we know that,

force = mass x acceleration

acceleration = $\frac{force}{mass}$

Here force is the summation of frictional force and horizontal component of the applied force. These force act in opposite directions.

force = $F_{k}$ - $F_{x}$

= 71.596 - 167.67

= -96.074

acceleration = $\frac{-96.074}{35}$

= -2.745 m/ $s^{2}$

6 0

3 years ago

Using pressure and density of fluids.

mario62 [17]

snow shoes.

shoes with large areas in contact with the snoow. reduces the pressure on the snow, and alows you to sink less. or to walk on the surface.

Stilettp high heels would have the opposite effect

7 0

3 years ago

What is the form of energy that is produced in all energy transformations?

Damm [24]

Answer: Long Answer...

Explanation: Most of the time, chemical energy is released in the form of heat, and this transformation from chemical energy to heat, or thermal energy, is called an exothermic reaction. Next, there are two main types of mechanical energy: kinetic energy and potential energy.

5 0

3 years ago