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MissTica
3 years ago
10

2. What makes Newton's 3rd Law an unbalanced force?​

Physics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

Explanation:

a

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Un cuerpo de 60 kg se encuentra a una distancia de 3.5 m del otro cuerpo, de manera que entre ellos se produce una fuerza de 6.5
aev [14]

Answer:

1989.6Kg

Explanation:

The computation of the mass of the other body is given below:

As we know that

F = G × m1 × m2 ÷ r²

Here the G would have the constant value i.e. 6.67 × 10^-11Nm² / kg².  

Now

6.5 × 10^-7N = 6.67 × 10^-11Nm² / kg² × 60Kg × m2 / (3.5m) ²

m2 = (F × r²) / (G × m1)

m2 = (6.5 × 10^-7N × (3.5m) ²) ÷ (6.67 × 10^-11Nm² / kg² × 60Kg)

= 1989.6Kg

7 0
3 years ago
Ano-ano ang mga kultural na pamayanan na matatagpuan sa Luzon?<br>Help. Po hirap po ako dito ​
Nitella [24]

Answer:

Kultural na Pamayanan sa Luzon

*Ifugao

*Kalinga

*Gaddang

Explanation:

Sana makatulong po sa inyu...

I tried to answered it...

Pero your welcome in advance..

(◍•ᴗ•◍)

3 0
3 years ago
Read 2 more answers
3. If an undetected air bubble was trapped inside the gas collection tube, how would this affect your calculated percent yield?
soldi70 [24.7K]
When an air bubble gets trapped inside the gas collection tube, then the gas that is actually collected becomes impure. This will definitely give an inaccurate result and the calculated percentage yield will be wrong. I hope that this is the answer that you were looking for and it has come to your help.
5 0
3 years ago
In the Bohr’s model of the hydrogen atom, the electron moves in a circular orbit of radius 5.041 × 10−11 m around the proton. As
Ilia_Sergeevich [38]

Answer:

The orbital speed of the electron is 2.296 x 10⁶ m/s

Explanation:

Given;

radius of the circular orbit, r = 5.041 × 10⁻¹¹ m

In the Bohr’s model of the hydrogen atom, the velocity of the electron is given as;

V = \frac{nh}{2\pi mr}

where;

h is Planck's constant

m is mass of electron

r is the radius of the circular orbit

n is the energy level of hydrogen in ground state

Substitute in these values and solve for V

V = \frac{nh}{2\pi mr} = \frac{1*6.626*10^{-34}}{2\pi *9.11 *10^{-31}*5.041*10^{-11}}\\\\V = 2.296*10^6  \ m/s

Therefore, the orbital speed of the electron is 2.296 x 10⁶ m/s

4 0
4 years ago
What is the same about the EM categories? What is different?
cricket20 [7]

Answer:

All 3 are CSS unit sizes which we can use for margins, fonts, borders etc.

Exp

CSS has four different unit sizes. These are:

Pixels (px)

Points (pt)

Ems (em)

Percentages(%)

These units are divided into two different groups. They are fixed and relative.

Pixels and points are fixed , whereas em and percentages are relative unit sizes. Relative unit sizes are good when creating scalable layouts.

Ems (em):

An em is a CSS unit that measures the size of a font. Originally, the em was equal to the width of the capital letter M, which is where its name originated.

It stands for "emphemeral unit" which is relative to the current font size.

The "em" is a scalable unit that  is used in web document media. Ems have mobile-device-friendly nature.

Pixels (px):

Pixels are fixed-size units that are used in screen media. One pixel is equal to one dot in computer. The problem with pixel unit is that it is not relative .

Points (pt):

Point values are only for print. A point is a unit of measurement use for real-life ink on paper. Generally, 72pts= 1 inch which is one real-life inch like on  a ruler. Point  is not recommended to use in web pages.

Generally, 1em=16px=12pt=100% if the body size is 100%.

Relative unit sized fonts change and fixed unit sized fonts remain the same.

For example,

body { font-size: 100%}

p{font-size: 16px}

8 0
3 years ago
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