Answer:
The purpose of a lab report is to organize and communicate what you did in your experiment.
Explanation:
<h3><u>Answer;</u></h3>
<em>-49 °C</em>
<h3><u>Explanation and solution;</u></h3>
- Considering the fact that, the specific heat capacity of aluminum is 0.903 J/g x C, and the heat of vaporization of water at 25 C is 44.0 KJ/mol.
Moles water = 0.48 g / 18.02 g/mol
=0.0266 moles
<em>Heat lost by water</em> = 0.0266 mol x 44.0 kJ/mol
=1.17 kJ => 1170 J
<em>But heat lost =heat gained</em>
<em>Therefore;</em> Heat gained by aluminium = 1170 J
1170 = 55 x 0.903 ( T - 25) = 49.7 T - 1242
1170 + 1242 = 49.7 T
T = 48.5 °C ( 49 °C <em>at two significant figures)</em>
<em>Hence</em>, final temperature = 49 °C
Answer:
A) ψ² describes the probability of finding an electron in space.
Explanation:
The Austrian physicist Erwin Schrödinger formulated an equation that describes the behavior and energies of submicroscopic particles in general.
The Schrödinger equation i<u>ncorporates both particle behavior</u>, in terms of <u>mass m</u>, and wave behavior, in terms of a <u><em>wave function ψ</em></u>, which depends on the location in space of the system (such as an electron in an atom).
The probability of finding the electron in a certain region in space is proportional to the square of the wave function, ψ². According to wave theory, the intensity of light is proportional to the square of the amplitude of the wave, or ψ². <u>The most likely place to find a photon is</u> where the intensity is greatest, that is, <u>where the value of ψ² is greatest</u>. A similar argument associates ψ² with the likelihood of finding an electron in regions surrounding the nucleus.
NO, it should not be the process is still the same . the only factors about it that should change is the experiment itself.:)
Answer:
58.0 g/mol
Explanation:
The reaction that takes place is:
- MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂
First we <u>calculate how many moles of silver chloride</u> were produced, using its <em>molar mass</em>:
- 6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl
Then we <u>convert AgCl moles into MCl₂ moles</u>, using the <em>stoichiometric ratio</em>:
- 0.0447 mol AgCl *
= 0.0224 mol MCl₂
Now we<u> calculate the molar mass of MCl₂</u>, using the original<em> mass of the sample</em>:
- 2.86 g / 0.0224 mol = 127.68 g/mol
We can write the molar mass of MCl₂ as:
- Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2
- 127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2
Finally we<u> calculate the molar mass</u> of M:
- Molar Mass of M = 57 g/mol
The closest option is 58.0 g/mol.