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4 years ago

Which one A or B Help Fast Now

Physics

2 answers:

spayn [35]4 years ago

6 0

Answer:

The answer is b, because it doesn't show any evidence that electricity is flowing

irga5000 [103]4 years ago

3 0

Answer:

the answer is b because it does not show evidence

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g determine what frequency is required of a source powering a 100 uf capacitor a 500 ohm resistor and a s50 mH inductor in serie

polet [3.4K]

Answer: $71.16\ Hz$

Explanation:

Given

Capacitance $C=100\ \mu F$

Resistance $R=500\ \Omega$

Inductance $L=50\ mH$

In LCR circuit, current is maximum at resonance frequency i.e.

$X_L=X_C\ \text{and}\ \omega_o=\dfrac{1}{\sqrt{LC}}$

Insert the values

$\Rightarrow \omega_o=\dfrac{1}{\sqrt{50\times 10^{-3}\times 100\times 10^{-6}}}\\\\\Rightarrow \omega_o=\dfrac{1}{\sqrt{5}\times 10^{-3}}\\\\\Rightarrow \omega_o=0.447\times 10^{3}$

Also, frequency is given by

$\Rightarrow 2\pi f=\omega_o\\\\\Rightarrow f=\frac{\omega_o}{2\pi}$

$\Rightarrow f=\dfrac{1}{2\pi}\times 0.447\times 10^3\\\\\Rightarrow f=71.16\ Hz$

8 0

3 years ago

Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Bat -10 m/s when th

tatiyna

Answer:

b) -10 m/s

Explanation:

In perfectly elastic head on collisions of identical masses, the velocities are exchanged with one another.

3 0

3 years ago

A copper transmission cable 140 {\rm km} long and 12.5 {\rm cm} in diameter carries a current of 115 {\rm A}.

SpyIntel [72]

Answer:

1. $V=22.0407\ V$

2. $Q=9126837\ J$

Explanation:

Given:

length of copper cable, $l=140\ km=1.4\times 10^5\ m$

diameter of copper cable, $d=12.5\ cm=0.125\ m$

current through the copper wire, $i=115\ A$

We have the resistivity of copper, $\rho=1.68\times10^{-8}\ \Omega.m$

We know that the resistance of a wire is given as:

$R=\rho.\frac{l}{a}$

where:

$a=$ cross sectional area of the wire

$R=1.68\times 10^{-8}\times\frac{140000}{\pi.\frac{0.125^2}{4} }$

$R=0.1917\ \Omega$

Now from the Ohm's law:

$V=R.i$

$V=0.1917\times 115$

$V=22.0407\ V$

From the Joules law the thermal energy generated as an effect of electrical energy is mathematically given as:

$Q=i^2.R.t$

where:

$t=$ time duration for which the current flows

$Q=115^2\times 0.1917\times 3600$ (∵ we have 3600 seconds in 1 hour)

$Q=9126837\ J$

5 0

3 years ago

A child has an ear canal that is 1.3 cm long. At what sound frequencies in the audible range will the child have increased heari

ElenaW [278]

Answer:

The answer to this is

6600 Hz to 19,800 Hz

Explanation:

The shape of the human ear is analogous to a closed ended pipe hence

we have λ = 4L or wavelength = 4 * length of the child ear

The frequency c/λ where c = speed of sound = 343 m/s

hence the child's audible range is multiples of 343/(4*0.13) =6600Hz

or 13200 Hz or 19,800 Hz

The generally quoted range of human hearing is 20 Hz to 20 kHz

7 0

3 years ago

Plz Helpp

marshall27 [118]

300

could i get brainiest

5 0

3 years ago