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vlada-n [284]
3 years ago
8

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10−6 M/s.

Which of the following would you expect after another 3 seconds?
Chemistry
1 answer:
Slav-nsk [51]3 years ago
8 0

The question is incomplete, the complete question is;

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10−6 M/s. Which of the following would you expect after another 3 seconds? a

The rate would be higher, and the concentration of reactants would be lower.

b

The rate would be higher, and the concentration of reactants would be higher.

c

The rate would be lower, and the concentration of reactants would be lower.

d

The rate would be lower, and the concentration of reactants would be higher.

Answer:

The rate would be lower, and the concentration of reactants would be lower.

Explanation:

The rate of reaction refers to how quickly or slowly the reactants disappear or the products appear in a given reaction. The rate of reaction depends on the concentration of the reactants. Thus, as concentration decreases with time, the rate of reaction decreases accordingly.

Therefore, reaction rates tend to decrease with time since the concentration of  the reactants decrease with time as the reactants are being converted into products. Thus after three seconds, the rate would be lower, and the concentration of reactants would be lower. Hence the answer above.

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how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4
Alinara [238K]
Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
               ↓              ↓
             2 moles     1 mole

2* 32 g O2 ----------> 1* 44 g CO2
     x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

x =  \frac{640}{44}

x = 14.54 g of O2





7 0
3 years ago
If a compound has a molar más of 180g/mol and it’s empirical formula is CH^2O, what is it’s molecular formula?
lesya [120]

C: 12.0107 g/mol ≅ 12.00 g/mol

H: 1.00784 g/mol ≅ 1.008 g/mol

O: 15.999 g/mol ≅ 16.00 g/mol

n(molar mass of CH2O)= 180

n.30=180

n=6

molecular formula: c6h12o6 glucose

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3 years ago
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2 years ago
The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i
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Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

Q=mc\Delta T +m\Delta H_{fusion}

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